Mass spectrum of open bosonic strings

In summary, the mass spectrum of an open string in light-cone gauge is determined by the values of N, which is related to the string length scale and the coefficients of the string's modes. For N=0, the string has a tachyon state, while for N=1, it has a massless vector boson state. This is due to the Lorentz invariance requirement. For N=2, the string has a single massive state with spin-2 and 324 states overall, in accordance with the representation theory of SO(25).
  • #1
snypehype46
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TL;DR Summary
This question regards some features about the excitation of an bosonic string
I'm learning string theory from the book by Zwiebach and others. I'm trying to understand the quantisation of the open string and its mass spectrum.

In light-cone gauge the mass-shell condition of an open string is given by:

$$M^2 = 2(N - 1)/l_s^2$$

where ##N = \sum_{i=1}^{D-2}\sum_{n=1}^\infty \alpha^i_{-n}\alpha^i_n## and ##l_s## is the string length scale.

Now to determine the mass spectrum of the string, we can look at the values of $N$:

- For ##N=0##, there is a tachyon since ##M^2## is negative
- For ##N=1##, there is a *vector boson* ##\alpha^i_-1 |0;k\rangle##.
- For ##N=2##, we have that ##M^2## is positive and the states are given by: ##\alpha^i_{-2}|0;k\rangle## and ##\alpha^i_{-1}\alpha^j_{-1}|0;k\rangle##

Now this is what I don't understand:

- Why is the state with ##N=1## a *vector*, why is not a scalar? How does one determine if a state is a vector or scalar?

- In the material I've read, it is claimed that Lorentz invariance requires that the the state with ##N=1## is massless, but I don't understand why is this case.

- Finally, the number of states with ##N=2## is claimed to 324 because it is the number of independent components of a matrix representation of ##SO(25)##, why is this? Also this state is said to have a single massive state with spin-2, why is this?
 
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  • #2
Your first question: for N=1 you have (D-2) components labeled by i, which transform into each other if you apply a Lorentz transfo. That's some pretty weird scalar, but it makes sense for a massless vector irrep.
 
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  • #3
Your 2nd: what do you get if you apply the momentum operator on the state and use the on-shell condition to calculate the mass (squared)? It should be zero, which is probably explained in Zwiebach.
 
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3d: this is basic representation theory for SO(N). A rep. for this group can always be written as the sum of an antisymmetric part (#=1/2×N(N-1)), a traceless symmetric part (#=1/2×N(N+1)-1) and a trace (#=1). See e.g. Zee's book on group theory.
 
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FAQ: Mass spectrum of open bosonic strings

What is the mass spectrum of open bosonic strings?

The mass spectrum of open bosonic strings refers to the set of possible mass states that the string can occupy. These mass states are derived from the quantization of the string's vibrations. The mass squared (m^2) of these states is given by the formula m^2 = (n-1)/α', where n is a non-negative integer and α' is the Regge slope parameter, related to the string tension.

What is the significance of the tachyon in the mass spectrum of open bosonic strings?

The tachyon is the lowest mass state in the spectrum of open bosonic strings, corresponding to n=0. Its mass squared is negative, indicating an imaginary mass. This suggests an instability in the theory, as the presence of a tachyon implies that the vacuum is not stable. The tachyon is a key feature that differentiates bosonic string theory from superstring theory, where tachyons are absent.

How are the higher mass states of open bosonic strings organized?

The higher mass states of open bosonic strings are organized into levels based on the integer n. Each level corresponds to a different set of vibrational modes of the string. For each level n, the mass squared is given by (n-1)/α', and the states can be classified by their symmetry properties and the number of oscillators excited.

What role does the Regge slope parameter (α') play in the mass spectrum?

The Regge slope parameter (α') is inversely related to the string tension and determines the spacing of the mass levels in the spectrum. It acts as a scaling factor for the mass squared of the states. A larger α' corresponds to a lower string tension and hence a more closely spaced mass spectrum, while a smaller α' means higher tension and more widely spaced masses.

Why is the ground state of open bosonic strings often considered problematic?

The ground state of open bosonic strings is considered problematic because it is a tachyonic state with negative mass squared, indicating an instability in the theory. This suggests that the vacuum state is not the true ground state and that the theory might need to be modified or extended to remove this instability. This issue is one of the reasons why bosonic string theory is not considered a complete theory of fundamental interactions, leading to the development of superstring theories which do not have tachyons.

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