- #1
phrox
- 40
- 1
First of all, I have to use all the limit laws I can to get these answers correct as the prof said.
1)
lim (3x^3 + 2x^2)
x->1/3
I factored out x^2, put the x^2 in front of the limit(constant multiple law), plugged in 1/3 into the x's, then multiplied everything together and got 1/3 for my answer. Is the only limit law that can be used the constant multiple law?
2)
lim (3x^(2/3) - 16x^-1
x->8
I don't even see any laws I can use in this, so I just plugged in 8, did the powers and third root of 64, etc etc. and got my final answer to be 10. There must've been a law I could've used, is there?
3)
lim (sqrt(w+2)+1) / (sqrt(w-3)-1)
w->7
I think I'm over-complicating this one, can I just use the quotient law and just plug the w in and solve by dividing top by bottom? This is how I tried to do 3:
multiplied by the top conjugate, so I multiplied top and bottom by sqrt(w+2)-1 and everything just went too big and complicated. Any help?
Thanks so much!
1)
lim (3x^3 + 2x^2)
x->1/3
I factored out x^2, put the x^2 in front of the limit(constant multiple law), plugged in 1/3 into the x's, then multiplied everything together and got 1/3 for my answer. Is the only limit law that can be used the constant multiple law?
2)
lim (3x^(2/3) - 16x^-1
x->8
I don't even see any laws I can use in this, so I just plugged in 8, did the powers and third root of 64, etc etc. and got my final answer to be 10. There must've been a law I could've used, is there?
3)
lim (sqrt(w+2)+1) / (sqrt(w-3)-1)
w->7
I think I'm over-complicating this one, can I just use the quotient law and just plug the w in and solve by dividing top by bottom? This is how I tried to do 3:
multiplied by the top conjugate, so I multiplied top and bottom by sqrt(w+2)-1 and everything just went too big and complicated. Any help?
Thanks so much!