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Slizzardman
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Homework Statement
A quarterback passes the football downfield at 20 m/s. It leaves his hand 1.8 m above the ground and is caught by a receiver 30 m away at the same height. What is the maximum height of the ball on its way to the receiver?
Xi=0m
Xf=30m
Yi=1.8m
Yf=1.8m
Vi= 20 m/s
t=1.5s (time in the air, aka delta t)
Homework Equations
Yf=Yi+(Vyi)t-.5g(t^2)
xf=xi+(vx)i*t
The Attempt at a Solution
xf-vi=t=1.5s
since this was a parabolic motion I used .75s as the time for max height. I plugged the numbers in and go 4.55625, or 4.56m max height. This came from the original 1.8m height added to .5g*(.75s^2) from the first equation, as Yi=1.8 and Vyi atthe halfway point of .75s was 0m/s.
There were no angles given. How have I screwed this up? Apparently my answer is wrong.