Mastering Tricky Antiderivatives for Exams: Integrals with Helpful Hints

  • Thread starter csi86
  • Start date
In summary, the conversation discussed two integrals that the person was struggling with and requested hints on how to solve them. The respondent provided hints and suggestions on how to approach the problems, such as using integration by parts and partial fractions. The conversation concluded with the person successfully solving the second integral and figuring out the correct solution for the first one.
  • #1
csi86
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0
I have to prepare for the exams and this is a set of integrals I can't do... some hints pls :

1.[tex] \int \frac{x}{\sqrt{x^{2}+2x+2}} \; dx [/tex]

2.[tex] \int \frac{x}{x^{3}+1} \; dx [/tex]

:confused:
Thank you for your time.
 
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  • #2
Hi and welcome to PF csi86!

You need to show some work before you receive help. What are your thoughts/ideas on these problem? What have you done till now, and where are you stuck?
 
  • #3
For the second try to solve

[tex] \frac{x}{x^{3}+1} =\frac{A}{x+1} +\frac{Bx+C}{x^{2}-x+1} [/tex]

Daniel.
 
  • #4
For the first one use integration by parts:

[tex] u = x [/tex][tex] dv = \frac{1}{\sqrt{1+(x+1)^{2}}}\; dx[/tex]
 
Last edited:
  • #5
Thank you, I have succesfully solved the second one, I might have done some mistakes :
[tex] -ln|x+1| + \frac{1}{2} ln{(x^{2}-x+1)} + \frac{2}{\sqrt{3}}\arctan{\frac{2x-1}{\sqrt{3}}} [/tex]
 
  • #6
Just don't forget the integration constant.

Daniel.
 
  • #7
Indeed , this might hurt in an exam. :redface:

I tried to solve the first one and I end up with :
[tex] \frac{x^{2}}{2 \sqrt{x^{2}+2x+2}} + \frac{1}{2} \int \frac{(x^{2})(2x+2)}{2 \sqrt{(x^{2}+2x+2})^{3}}} \;dx [/tex]

(Using integration by parts)
 
  • #8
Write it like that

[tex] \int \frac{x}{\sqrt{x^{2}+2x+2}} \ dx =\frac{1}{2}\int \frac{d(x^{2}+2x+2)}{\sqrt{x^{2}+2x+2}} -\int \frac{dx}{\sqrt{x^{2}+2x+2}} [/tex]

Daniel.
 
  • #9
I figured it out, thanks for the help Daniel. :)

I end up with :
[tex] \sqrt{x^{2}+2x+2} - \ln{(x+1+ \sqrt{x^{2}+2x+2})} [/tex]

I don't know if that is correct but I honestly hope so :).
 

FAQ: Mastering Tricky Antiderivatives for Exams: Integrals with Helpful Hints

What are antiderivatives and why are they important for exams?

Antiderivatives are the inverse operation of derivatives. They are important for exams because they allow us to find the original function from its derivative, which is often necessary to solve problems in calculus.

What makes antiderivatives tricky and how can I master them?

Antiderivatives can be tricky because there is no one set rule for finding them. Instead, you must use a combination of techniques such as substitution, integration by parts, and trigonometric identities. To master antiderivatives, it is important to practice and familiarize yourself with these techniques.

What are some helpful hints for solving tricky antiderivatives?

One helpful hint is to look for patterns in the function and try to use known antiderivative formulas. Another hint is to try different techniques if one approach is not working. Additionally, make sure to always double check your work and simplify your final answer.

How can I improve my speed in solving tricky antiderivatives during exams?

The key to improving speed is practice. The more you practice solving antiderivatives, the more familiar you will become with the different techniques and the quicker you will be able to recognize which technique to use for a given problem. It is also helpful to work on your algebra skills to simplify your calculations.

Are there any common mistakes to watch out for when solving tricky antiderivatives?

One common mistake is forgetting to add the constant of integration when finding the antiderivative. Another mistake is not simplifying the final answer, which can lead to incorrect solutions. It is also important to pay attention to the limits of integration and adjust accordingly when solving definite integrals.

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