- #1
eyanveom
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I have a question on an assignment that's due at 11:55 tonight. Here is the question:
Compute the intersection of a line and an ellipse centered at (0,0). Ellipse equation is b²x² + a²y² = a²b²
where b is the minor axis and a is the major axis.
I am having trouble finding A, B, and C- somewhere down the line, I know the Quadratic Eq. is used to find x. I also know AX² + BX + C = 0 is used. I've combined the slope (y = mx + c) into the ellipse equation ==> b²x² + a² (mx+c)² = a² b². I then distributed the a², yielding b²x² + (a²mx + a²c)² = a²b². Here is where I'm stuck. I know that ultimately I am trying to find A, B, and C.
A= (a²mx + a²c)²??
B= ??
C= b²x² - a²b²?? I am SO lost and confused! lol
Compute the intersection of a line and an ellipse centered at (0,0). Ellipse equation is b²x² + a²y² = a²b²
where b is the minor axis and a is the major axis.
I am having trouble finding A, B, and C- somewhere down the line, I know the Quadratic Eq. is used to find x. I also know AX² + BX + C = 0 is used. I've combined the slope (y = mx + c) into the ellipse equation ==> b²x² + a² (mx+c)² = a² b². I then distributed the a², yielding b²x² + (a²mx + a²c)² = a²b². Here is where I'm stuck. I know that ultimately I am trying to find A, B, and C.
A= (a²mx + a²c)²??
B= ??
C= b²x² - a²b²?? I am SO lost and confused! lol