Matching interaction terms and decay processes in standard model

In summary, the only interaction terms in the Standard Model that allow the given decay process are contained in the charged current interactions. These interactions are described by the Lagrangian term ##\mathcal{L}_{cc}## and involve both the left-handed fields and the projection operator. The first two questions confirm that the vertex between quarks is only allowed by the term ##ie_{W}W_{\mu}^{+} V_{mn}\bar{u}'_{m}\gamma^{\mu}(1+\gamma_{5})d'_{n}## because the down quark must not have a bar on top of it. Similarly, the third question confirms that the vertex between leptons is only allowed by the term ##
  • #1
spaghetti3451
1,344
34
I would like to consider the interaction terms in the Standard Model which allow the following decay process:

63e599fafd.png


The only interaction terms in the Standard Model which allow this decay process are contained in the charged current interactions:

$$\mathcal{L}_{cc}
= ie_{W}\big[W_{\mu}^{+}(\bar{\nu}'_{m}\gamma^{\mu}(1+\gamma_{5})e'_{m} + V_{mn}\bar{u}'_{m}\gamma^{\mu}(1+\gamma_{5})d'_{n})
+ W_{\mu}^{-}(\bar{e}'_{m}\gamma^{\mu}(1+\gamma_{5})\nu'_{m} + (V^{\dagger})_{mn}\bar{d}'_{m}\gamma^{\mu}(1+\gamma_{5})u'_{n})\big].$$

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1. Is the vertex between the quarks only allowed by the term ##ie_{W}W_{\mu}^{+} V_{mn}\bar{u}'_{m}\gamma^{\mu}(1+\gamma_{5})d'_{n}##?

2. Is this because the down quark enters the vertex and therefore must not have a bar on top of it?

3. Simialrly, is the vertex between the leptons only allowed by the term ##ie_{W}W_{\mu}^{-} (V^{\dagger})_{mn}\bar{d}'_{m}\gamma^{\mu}(1+\gamma_{5})u'_{n}##?
 
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  • #2
You are missing minus signs in your projection operators. CC iteractions act on left-handed fields only.

1,2) Yes.

3) No, you need the lepton fields in the operator.
 
  • #3
Orodruin said:
You are missing minus signs in your projection operators. CC iteractions act on left-handed fields only.

But the left-handed projection operator has a plus sign in the mostly positive metric, does it not? I'm using Cliff Burgess's textbook, although I should be using mostly negative because it is the common usage in the particle physics community.

Orodruin said:
3) No, you need the lepton fields in the operator.

Right, my bad.
 

FAQ: Matching interaction terms and decay processes in standard model

1. What is the Standard Model?

The Standard Model is a theory in particle physics that describes the fundamental particles and their interactions. It is considered the most successful and widely accepted theory of particle physics, as it has been able to accurately predict and explain a wide range of experimental results.

2. What are interaction terms in the Standard Model?

Interaction terms in the Standard Model refer to the mathematical expressions that describe how particles interact with each other. These terms are crucial in understanding the behavior of particles and predicting their decay processes.

3. How are interaction terms and decay processes related?

Interaction terms and decay processes are closely related in the Standard Model. The interaction terms determine how particles interact with each other, and these interactions can lead to various decay processes where particles transform into other particles.

4. How do scientists match interaction terms and decay processes in the Standard Model?

Scientists match interaction terms and decay processes in the Standard Model through experimental measurements and theoretical calculations. By studying the behavior of particles and their interactions, scientists can determine the appropriate interaction terms and predict the resulting decay processes.

5. Why is it important to match interaction terms and decay processes in the Standard Model?

Matching interaction terms and decay processes in the Standard Model is important because it allows scientists to better understand the fundamental particles and their behavior. It also helps in predicting and interpreting experimental results, which can lead to new discoveries and advancements in particle physics.

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