- #1
ra_forever8
- 129
- 0
Consider the predator-prey system defined by
\begin{equation} \frac{dP}{dt}= aP(1-\frac{N}{K})-bPN= f(N,P)----------(1)
\end{equation}
\begin{equation} \frac{dN}{dt}=cNP-dP= g(N,P)--------------(2)
\end{equation}
with initial conditions $P=P_{0}$ and $N=N_{0}$,
Where $N=N(t)$ is the prey density and $P=P(t)$ is the predator density. Here $a,b,c,d$ and $K$ are all positive constants.
Non-dimensionalise equations (1) and (2) to obtain
\begin{equation} \frac{du}{d\tau}=u(1-u-v)= f(u,v)
\end{equation}
\begin{equation} \frac{dv}{d\tau}=\alpha v(u-\beta)= g(u,v)
\end{equation}
with $u=u_{0}$ and $v=v_{0}$,
where $\alpha = \frac{cK}{a}$ and $\beta= \frac{d}{cK}$=> I try to do by saying Non-dimensionalise parameter to be
$P= au$, $N=Xv$ and $t=\frac{\tau}{a}$, where I can choose $X= \frac{K}{b}$, but it did not works. can anyone please help to get Non-dimensionalise equations.
\begin{equation} \frac{dP}{dt}= aP(1-\frac{N}{K})-bPN= f(N,P)----------(1)
\end{equation}
\begin{equation} \frac{dN}{dt}=cNP-dP= g(N,P)--------------(2)
\end{equation}
with initial conditions $P=P_{0}$ and $N=N_{0}$,
Where $N=N(t)$ is the prey density and $P=P(t)$ is the predator density. Here $a,b,c,d$ and $K$ are all positive constants.
Non-dimensionalise equations (1) and (2) to obtain
\begin{equation} \frac{du}{d\tau}=u(1-u-v)= f(u,v)
\end{equation}
\begin{equation} \frac{dv}{d\tau}=\alpha v(u-\beta)= g(u,v)
\end{equation}
with $u=u_{0}$ and $v=v_{0}$,
where $\alpha = \frac{cK}{a}$ and $\beta= \frac{d}{cK}$=> I try to do by saying Non-dimensionalise parameter to be
$P= au$, $N=Xv$ and $t=\frac{\tau}{a}$, where I can choose $X= \frac{K}{b}$, but it did not works. can anyone please help to get Non-dimensionalise equations.