Maths Integration Problem HELP

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In summary, the problem is to integrate (2x-1)/√x and the solution involves splitting the equation into two parts and integrating them separately. The final answer is (4/3)x^(3/2). In a similar problem, (1-4x)/(x*√x), the solution involves simplifying the fraction and then integrating, resulting in the answer of -4/3x^(3/2).
  • #1
susperia_knvb
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Maths Integration Problem! HELP!

Homework Statement


ok maths problems is like this:
2.g. integrate (2x-1)/*square root x*

The Attempt at a Solution



ok. i split the equation up so that i am integrating 2x/*root x* - 1/*root x*

the 1/root x integrates to - 2x^(1/2) and the constant is present (+c)

but i cannot seem to integrate the (2x)/(x^(1/2))
the answer is (4/3)x^(3/2)... but i can't seem to get it... even working backwards.
 
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  • #2
Can you simplify [tex]\frac{x}{\sqrt{x}}[/tex] ?
 
  • #3
take the two out the front of the integral sign and then multiply?
 
  • #4
ok. i don't get where the x^(3/2) comes from.
[tex]\frac{x}{\sqrt{x}}[/tex]
becomes x.x^(-1/2)... then we add the powers?
= x^(1/2)?
 
  • #5
Yes, correct. Can you integrate now?
 
  • #6
Yes, correct. Can you integrate now?
 
  • #7
x^(1/2) becomes (2/3)x^3/2) then multiplying in the two becomes...

(4/3)x^(3/2) which is correct yeh?

cool :D



ok another one. (1-4x)/(x*root*x)... i can't do the (4x)/(x^(3/2))
 
  • #8
[tex] 4 \cdot \frac{x}{x^{1.5}}= 4 \cdot x^{-1/2}[/tex]
 
  • #9
damn it. lol. how stupid of me. missed the cancelling there totally. ah! no wonder i could do the rest of the chapter *shakes head*
 

FAQ: Maths Integration Problem HELP

What is the purpose of integration in mathematics?

Integration is used to find the area under a curve or the accumulation of a function. It is also used to solve problems in physics, engineering, economics, and many other fields.

How do I solve a basic integration problem?

To solve a basic integration problem, you can use the fundamental theorem of calculus, which states that the integral of a function is equal to the antiderivative of that function. You can also use integration techniques such as substitution, integration by parts, or partial fractions.

What is the difference between indefinite and definite integration?

Indefinite integration is used to find the general antiderivative of a function, while definite integration is used to find the definite integral between two specific limits. In other words, indefinite integration gives a function, while definite integration gives a number.

How do I know which integration technique to use?

The choice of integration technique depends on the form of the function being integrated. You can use substitution when the function contains a variable raised to a power, integration by parts when the function is a product of two functions, and partial fractions when the function is a ratio of polynomials.

What are some real-life applications of integration?

Integration is used in various fields such as physics, engineering, economics, and statistics. Some examples of real-life applications include calculating the area under a velocity-time graph to determine distance traveled, finding the volume of irregularly shaped objects, and calculating the net change in a population over time.

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