Matlab Second Derivative Ploting Problem

[el_pohl]

Hello, this is my first post in this site, so here goes:

Im working on a Matlab program. I have to calculate the second derivative of a given equation. The problem is that plotting the derivative is necessary, and that's where I'm stuck.

Here's what I've got so far:

% Evaluar f(x) y f'(x) usando diferencias hacia atras.
%
x = -10:0.1:10;
f = x.^3 - 5*x.^2 + 2*x + 8;
df = diff(f);
dx = diff(x);
df_dx = df./dx;
xd = x(2:length(x));
d2f = diff(f,2);
d2x = diff(f,2);
d2f_d2x = d2f./d2x;
%
% Graficar lo anterior.
%
subplot(2,1,1),...
plot(x,f,xd,df_dx,xd,d2f_d2x),...
title('Derivada de un polinomio de quinto grado'),...
xlabel('x'),grid,...
ylabel('f(x)'),...
axis([-4,5,-500,1500]);

On the internet I found out that diff(f,2) would calculate the second diff, I guess that's true. Ignore the spanish text :P.

When I try to run the program, the following appears:

? Error using ==> plot
Vectors must be the same lengths.

Error in ==> C:\MATLAB6p5\work\segunda_diferencial.m
On line 16 ==> plot(x,f,xd,df_dx,xd,d2f_d2x),...

Hope you can help.

Thanks!

 

[Clausius2]

De donde eres? Casi no se nota que hablas español.


Well, the command line "diff" shortens one dimension the array:

$$diff (\overline{x})=[x_2-x_1, x_3-x_2,...x_n-x_{n-1}]$$

you will obtain a n-1 array dimension.

You should interpolate the last component from interior ones, in order to have n components.

With diff2 is the same, surely you will obtain n-2 components.

 

[el_pohl]

Gracias! Soy del norte de México.

In fact, I can graph the first diff, though what you say does make sense, as with every consecutive derivative one constant term will dissappear.

Interpolate? As with 'interp1'? The last component? d2f_d2x in my code?

Casi no se nada de Matlab :(

Thanks for that, I will try it out, hope I understood you...

 

[el_pohl]

Ok, I got it! Thanks though.