Matrices of Linear Transformations .... Poole, Example 6.76 ....

[Math Amateur]

I am reading David Poole's book: "Linear Algebra: A Modern Introduction" (Third Edition) and am currently focused on Section 6.6: The Matrix of a Linear Transformation ... ...

I need some help in order to fully understand Example 6.76 ... ...

Example 6.76 reads as follows:View attachment 8770
View attachment 8771
My question or issue of concern is as follows:When we calculate transformation outputs from inputs using \(\displaystyle T \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} x - 2y \\ x + y - 3z \end{bmatrix}\)

... it appears, as if by default, that we are using \(\displaystyle \{ e_1, e_2 , e_3 \}\) and \(\displaystyle \{ e_1, e_2 \}\) as bases for \(\displaystyle \mathbb{R}^3\) and \(\displaystyle \mathbb{R}^2\) respectively ...

... BUT ...Poole states that the bases are \(\displaystyle \mathcal{B} = \{ e_1, e_2 , e_3 \}\) and \(\displaystyle \mathcal{C} = \{ e_2, e_1 \}\)... ?So, in the example, it seems that \(\displaystyle T\) is defined in terms of \(\displaystyle \{ e_1, e_2 , e_3 \}\) and \(\displaystyle \{ e_1, e_2 \}\) ... and then we recalculate to find the matrix of \(\displaystyle T\) with respect to \(\displaystyle \mathcal{B}\) and \(\displaystyle \mathcal{C}\) ... ...Can someone explain what is going on here ... shouldn't \(\displaystyle T\) be defined in terms of the declared bases \(\displaystyle \mathcal{B}\) and \(\displaystyle \mathcal{C}\) ... so that \(\displaystyle T\) takes an input in terms of \(\displaystyle \mathcal{B}\), and then give an output in terms of \(\displaystyle \mathcal{C}\) ... ...Hope someone can clarify the above issue ...

Help will be appreciated ..

Peter

 

[I like Serena]

Note that $\mathcal C$ has the standard unit vectors swapped.
So it is non-standard.
And that's what we see in the matrix of the end result as well. That is, the rows are swapped.

 

[Math Amateur]

Note that $\mathcal C$ has the standard unit vectors swapped.
So it is non-standard.
And that's what we see in the matrix of the end result as well. That is, the rows are swapped.

Thanks Klaas ...

Peter