Max Height & Time In Air of Ball Thrown Upward from 25m

In summary, the ball is thrown upwards from a height of 25 m with an initial speed of 11 m/s. The maximum height the ball reaches is 31 m, and to find the time the ball is in the air, you can use the equations s=ut+4.9t^2 and v=u+at. To find the time taken to reach the ground, you double the time it takes to reach the maximum height and add it to the time it takes to reach the height it was thrown from.
  • #1
sp00ky
22
0
A ball is thrown straigh up, from height of 25 m above the ground, at a speed of 11 m/s.
The first question is what is the max. height of the ball above the ground.
I got that one it's like 31m. But there was another question after that that asks how long is the ball in the air. What equation must I use to find this out?
 
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  • #2
When does the ball 'stop' being in the air?
 
  • #3
well first find the time taken to reach the max ht. double this time it is the time taken for the ball to reach the ht it was thrown from(25m ) at this pt the ball has a speed of 11m/s use s =ut+4.9t^2 to find this t2 add this to t1 and that is the time taken to reach the ground. to find time to reach max ht use v = u+at.
 

FAQ: Max Height & Time In Air of Ball Thrown Upward from 25m

What factors affect the maximum height and time in air of a ball thrown upward from a height of 25m?

The maximum height and time in air of a ball thrown upward from 25m are primarily affected by the initial velocity of the ball, the angle at which it is thrown, and the force of gravity. Other factors such as air resistance and the mass of the ball may also play a role.

How can the maximum height and time in air be calculated for a ball thrown upward from 25m?

The maximum height can be calculated using the equation h = (v02sin2θ)/2g, where v0 is the initial velocity, θ is the angle at which the ball is thrown, and g is the acceleration due to gravity. The time in air can be calculated using the equation t = (2v0sinθ)/g.

What is the relationship between the maximum height and time in air for a ball thrown upward from 25m?

The maximum height and time in air have a direct relationship. This means that as the maximum height increases, the time in air also increases. This is because a higher maximum height requires the ball to travel for a longer period of time before reaching the ground.

How does air resistance affect the maximum height and time in air of a ball thrown upward from 25m?

Air resistance can decrease the maximum height and time in air of a ball thrown upward from 25m. This is because air resistance acts as a force that opposes the motion of the ball, slowing it down and reducing its maximum height and time in air.

Can the maximum height and time in air of a ball thrown upward from 25m ever be equal to zero?

Yes, it is possible for the maximum height and time in air of a ball thrown upward from 25m to be equal to zero. This would occur if the ball is thrown with an initial velocity of zero or if it is thrown straight upward at a 90-degree angle, meaning it does not travel horizontally at all. In these cases, the ball would reach its maximum height of 25m and then immediately fall back to the ground, resulting in a time in air of zero.

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