Max Speed of Piston in Simple Harmonic Motion

In summary, the motion of a piston in an automobile engine can be represented as simple harmonic motion. To find the maximum speed of the piston, we need to convert the engine's rotational speed from 3000 rpm to 314.159 rad/sec. The amplitude of the motion can be determined by dividing the total distance traveled by the piston (10 cm) by 2. Using the equations for kinetic and potential energy, we can formulate an equation for total energy (E) in terms of the spring constant (k) and amplitude (A). The maximum velocity can then be calculated using the formula vmax = wA, where w is the angular velocity. Finally, plugging in the values for w and A, we can find the maximum
  • #1
Dark Visitor
215
0
The motion of a piston in an automobile engine is nearly simple harmonic. If the 1 kg piston travels back and forth over a total distance of 10 cm, what is the maximum speed (magnitude of velocity) when the engine is running at 3000 rpm? (Hint: the 10 cm distance has something to do with amplitude; 3000 rpm needs to be converted to rad/sec)


I did convert the 3000 rpm, and I got 314.159 rad/sec.


I need some help with this problem a.s.a.p. I don't know where to go with it. Thanks for any help you can give me.
 
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  • #2
What formula do you think you will need here?
 
  • #3
I don't know, and I don't know any way to find A. I keep thinking that A has something to do with the 3000 rpm, but I am not sure.
 
  • #4
What formula(s) do you know that would allow you to find the maximum velocity?
 
  • #5
Dark Visitor said:
I don't know, and I don't know any way to find A. I keep thinking that A has something to do with the 3000 rpm, but I am not sure.

A is the amplitude. If the piston moves, from minimum to maximum, a distance of 10cm, what distance does it move when it goes from 0 to maximum?
 
  • #6
5 cm? Cause 10 cm would be the total length, while +A is half, and -A is the other half.
 
  • #7
Dark Visitor said:
5 cm? Cause 10 cm would be the total length, while +A is half, and -A is the other half.

Right good. Now can you formulate an equation for speed given kinetic energy is 1/2mv2 and potential energy is 1/2kx2. What is the formula for the total energy?
 
  • #8
E = K + U

(K is kinetic energy, u is potential energy)

But using the equations you gave, I am missing most of the quantities. How can I use them?
 
  • #9
Dark Visitor said:
E = K + U

(K is kinetic energy, u is potential energy)

But using the equations you gave, I am missing most of the quantities. How can I use them?

I told you K and U, if you get an expression for E, you will get what you need with the quantities you know.
 
  • #10
But for K, I need a velocity, which I don't have.

And for U, I need a spring constant value for k, but we have x (10 cm).
 
  • #11
Dark Visitor said:
But for K, I need a velocity, which I don't have.

And for U, I need a spring constant value for k, but we have x (10 cm).

you don't need to plug in all the values at one time. Just formulate and then see if you can get the terms needed.

what is E in terms of k and A?
 
  • #12
Well since I don't have all the values I need, I get:

K = 1/2(1 kg)(v)2

and

U = 1/2(k)(.01 m)2

and then we still have E = K + U
 
  • #13
Dark Visitor said:
Well since I don't have all the values I need, I get:

K = 1/2(1 kg)(v)2

and

U = 1/2(k)(.01 m)2

and then we still have E = K + U

do not put in the values as yet.

[tex]E=\frac{1}{2}mv^2+\frac{1}{2}kx^2[/tex]

Do you know another way to re-write E in terms of k and A?
 
  • #14
I think what is being asked for is an equation that resembles the other oscillators.


x(t)=A Sin(argument in t) where your argument has you hitting both extremes at a rate of 50 times a second, say by multiplying t by something like 100 * pi (314.15)
Now remember to get the max velocity, you need to know when acceleration is zero.
The velocity is -wA sin(wt). sin(wt) is at most 1.0. Hope this helps, I've been at this most of the day and am burnt to a crisp.
 
  • #15
So do I use the equation:

vmax = wA ? Or what? I am really confused on this one...
 
  • #16
Dark Visitor said:
So do I use the equation:

vmax = wA ? Or what? I am really confused on this one...
YES! Vmax=wA. Good job. Sorry if I'm a little fried and testy.
 
  • #17
Dark Visitor said:
So do I use the equation:

vmax = wA ? Or what? I am really confused on this one...


yes, had you derived it, you would get [itex]v_{max}=\omega A[/itex]
 
  • #18
No, don't be. I owe you big time for all of your help today, and I would be the same way if I was helping someone like me.

Now that I got that right, where do I get my w and A values?
 
  • #19
Dark Visitor said:
No, don't be. I owe you big time for all of your help today, and I would be the same way if I was helping someone like me.

Now that I got that right, where do I get my w and A values?

A is the amplitude that you found, and w is the angular velocity you converted in the first post.
 
  • #20
Okay, and I got:

vmax = (314.159 rad/s)(.05 m)
= 15.71 m/s


Thanks a lot, both of you, for your help. I appreciate it more than you know. :redface:
 

FAQ: Max Speed of Piston in Simple Harmonic Motion

What is the maximum speed?

The maximum speed is the fastest possible velocity that an object can reach.

How do you find the maximum speed of an object?

The maximum speed can be found by calculating the object's acceleration and using it to determine the maximum velocity that can be achieved.

Why is it important to find the maximum speed of an object?

Knowing the maximum speed of an object is important for understanding its capabilities and potential limitations.

Can the maximum speed of an object change?

Yes, the maximum speed of an object can change depending on various factors such as external forces, changes in the object's mass or shape, and the medium it is moving through.

Is there a limit to the maximum speed an object can reach?

According to the theory of relativity, the speed of light is the ultimate speed limit in the universe. However, this limit may not apply to objects with zero mass, such as photons.

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