- #1
2slowtogofast
- 135
- 1
A cylindrical torsion bar made of steel (E = 209 GPa) with diameter of 20mm. The allowable shear stress for this material is 200 MPa what is the max torque that can be safely applied to this bar.
[tex]\tau[/tex] = Tr / J
[tex]\tau[/tex] = shear stress
T = torque
r = radius
J= second polar moment of area
I was thinking of using this formula but I would not have used E = 209GPa in my solution is this wrong? If so could somebody point me in the right direction.
[tex]\tau[/tex] = Tr / J
[tex]\tau[/tex] = shear stress
T = torque
r = radius
J= second polar moment of area
I was thinking of using this formula but I would not have used E = 209GPa in my solution is this wrong? If so could somebody point me in the right direction.