Max Volume of Cylinder Inscribed in Cone: 10r^3π

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To find the maximum volume of a cylinder inscribed in a cone with height 10 and base radius 3, the relationship between the cylinder's height and radius is established using similar triangles, leading to the equation h = 10 - (10/3)r. Substituting this into the volume formula V = πr²h results in V = 10π(r² - (r³/3)). To maximize the volume, differentiate this expression with respect to r and set the derivative equal to zero. This approach allows for the determination of the optimal dimensions of the cylinder for maximum volume.
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Homework Statement


A right circular cylinder in inscribed in a cone with height 10 and base radius 3. Find the largest possible voluem of such a cylinder.

Homework Equations


V=\pi*r^2*h



The Attempt at a Solution


Ok, so I used similar triangles of the cone and cylinder to obtain h=(10/3)r
I substituted that in for h and I'm not sure where to go from there.
 
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Volume or surface area? What level of calculus is this? Were you trying to give the volume of a cone or of the cylinder? I would solve the problem with calculus of variations by minimizing the integral of the surface area, but that is something that requires differential equations.
 
Calc 1, we are trying to maximize the volume of a cyclinder inside a cone with the given information.
 
Weave said:

Homework Statement


A right circular cylinder in inscribed in a cone with height 10 and base radius 3. Find the largest possible voluem of such a cylinder.

Homework Equations


V=\pi*r^2*h



The Attempt at a Solution


Ok, so I used similar triangles of the cone and cylinder to obtain h=(10/3)r
I substituted that in for h and I'm not sure where to go from there.
Look more closely at your similar triangles. You have a large triangle (the entire cone) and a small triangle (the area inside the cone above the cylinder). If the cylinder has height h and radius r, then similar triangles gives (10-h)/r= 10/3 or 10-h= (10/3)r so h= 10- (10/3)r= 10(1- r/3). Putting that into V= \pi r^2 h gives V= 10\pi (r^2- r^3/3). Differentiate that with respect to r and set the derivative equal to 0.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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