Maxima and Minima (vector calculus)

In summary, the author discusses a function $f(x,y) = (x^2+y^2)e^{-(x^2+y^2)}$ and its graph on the unit circle $x^2+y^2=1$. The author suggests that the graph may have a local maximum at (x,y) on the unit circle and questions why this may be the case. They also inquire about how to plot this function in various graphing calculators and note that the function can be written in cylindrical coordinates as $f(r,\theta)=r^2e^{-r^2}$ and in the form $y=x^2e^{x^2}$. The graph of the latter form shows that there are points of interest
  • #1
WMDhamnekar
MHB
381
28
Hi, Hi,

Author said If we look at the graph of $ f (x, y)= (x^2 +y^2)*e^{-(x^2+y^2)},$ as shown in the following Figure it looks like we might have a local maximum for (x, y) on the unit circle $ x^2 + y^2 = 1.$

1649834173266.png
But when I read this graph, I couldn't guess that the stated function have a local maximum on the unit circle $ x^2 + y^2=1$

1)I want to know what did author grasp in the above figure which compelled him to make the aforesaid statement?

2) How to plot this function in 'R' or in 'GNU OCTAVE' or in any graphing calculator ? Is it easy to plot $f(x,y)= (x^2+y^2)*e^{-(x^2+y^2)} ?$
 
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  • #2
Do you notice that the only way x and y appear in that function is as "$x^2+y^2$"? In cylindrical coordinates we can write it as $f(r,\theta)= r^2e^{-r^2}$. If we write it as $y= x^2e^{x^2}$ its graph looks like this: <iframe src="https://www.desmos.com/calculator/oj7v5yfd0f?embed" width="500" height="500" style="border: 1px solid #ccc" frameborder=0></iframe>

Do you see what happens at x= 1 and x= -1? Imagine rotating that around the y-axis.
 

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