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How would I find the maximum area of a triangle given a fixed perimeter?
I assume that it would be an equilateral triangle, but I'm finding it very hard proving it.
I started by drawing a triangle of side lengths a, b and P -(a+b) with angles of alpha, beta and gamma.
I then used the A=(ab*sine(gamma))/2 formula for the area. But have been hitting a definite brick wall. I'm guessing calculus is necessary, but I'm struggling to see how.
Can anyone help?
Thanks,
Unredeemed.
I assume that it would be an equilateral triangle, but I'm finding it very hard proving it.
I started by drawing a triangle of side lengths a, b and P -(a+b) with angles of alpha, beta and gamma.
I then used the A=(ab*sine(gamma))/2 formula for the area. But have been hitting a definite brick wall. I'm guessing calculus is necessary, but I'm struggling to see how.
Can anyone help?
Thanks,
Unredeemed.