Maximizing a Complex Function: Solving the Optimization Challenge II

In summary, the Optimization Challenge II is a scientific competition open to individuals and teams with a background in science, mathematics, or computer science. The winner is determined by evaluating submitted solutions against pre-determined criteria, with the deadline for submissions being announced at the start of the competition. Prizes are awarded to the winner, with the specifics being announced at the start of the challenge.
  • #1
anemone
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Find the maximum value of the function $\sqrt{x^4-9x^2-12x+61}-\sqrt{x^4-x^2+1}$.
 
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  • #2
My Solution:

Given \(\displaystyle \displaystyle \sqrt{x^4-9x^2-12x+61}-\sqrt{x^4-x^2+1} = \sqrt{\left(x^2-5\right)^2+\left(x-6\right)^2}-\sqrt{\left(x^2-1\right)^2+(x-0)^2}\)

Now Using Triangle Inequality::

\(\displaystyle \displaystyle \sqrt{\left(x^2-5\right)^2+\left(x-6\right)^2}-\sqrt{\left(x^2-1\right)^2+(x-0)^2}\leq \sqrt{\left(x^2-5-x^2+1\right)^2+\left(x-6-x\right)^2} = 2\sqrt{13}\)

and equality hold when \(\displaystyle \displaystyle \frac{x^2-5}{x-6} = \frac{x^2-1}{x}\)
 
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  • #3
jacks said:
My Solution:

Given \(\displaystyle \displaystyle \sqrt{x^4-9x^2-12x+61}-\sqrt{x^4-x^2+1} = \sqrt{\left(x^2-5\right)^2+\left(x-6\right)^2}-\sqrt{\left(x^2-1\right)^2+(x-0)^2}\)

Now Using Triangle Inequality::

\(\displaystyle \displaystyle \sqrt{\left(x^2-5\right)^2+\left(x-6\right)^2}-\sqrt{\left(x^2-1\right)^2+(x-0)^2}\leq \sqrt{\left(x^2-5-x^2+1\right)^2+\left(x-6-x\right)^2} = 2\sqrt{13}\)

and equality hold when \(\displaystyle \displaystyle \frac{x^2-5}{x-6} = \frac{x^2-1}{x}\)

Well done, jacks!(Yes) That is the trick to make this challenge as simplest as possible, and thanks for participating!:)
 

FAQ: Maximizing a Complex Function: Solving the Optimization Challenge II

What is the Optimization Challenge II?

The Optimization Challenge II is a scientific competition designed to find the best solution to a given problem through the use of mathematical and computational methods.

How is the winner determined in the Optimization Challenge II?

The winner of the Optimization Challenge II is determined by evaluating the performance of submitted solutions against a set of pre-determined criteria. The solution with the highest score will be declared the winner.

Who can participate in the Optimization Challenge II?

The Optimization Challenge II is open to anyone with a background in science, mathematics, or computer science. Both individuals and teams can participate in the competition.

What is the deadline for submitting solutions in the Optimization Challenge II?

The deadline for submitting solutions in the Optimization Challenge II is typically announced at the start of the competition. It is important to submit solutions before the deadline to be considered for evaluation.

Are there any prizes for the winner of the Optimization Challenge II?

Yes, there are prizes for the winner of the Optimization Challenge II. The specific prizes will be announced at the start of the competition and may vary depending on the sponsor and theme of the challenge.

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