- #1
Aerstz
- 36
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- Homework Statement
- Calculate the stress in a screw thread resulting from a known force
- Relevant Equations
- Stress = Force / (0.25 * pi * (nominal thread diameter - 0.93194 * pitch)^2
A load of 100 kg acting in the axial direction is applied to a nut coupled with a standard M10 bolt. The nominal thread diameter is 10 mm; pitch is 1.5 mm. Thus, the stress acting on a single thread in the bolt is:
1000 N / (0.25 * pi * (10 mm - 0.93194 * 1.5 mm)^2) ≈ 17.21 MPa
17 MPa seems rather low. If a nut covers 5-threads, the total stress is therefore just 3 MPa (17/5), translating to a maximum load acting on the steel nut (assuming proof strength of ~200 MPa) of approximately 10-tons.
10-tons seems a lot of weight before a loaded M10 nut will strip a bolt of its threads, which is why I'm posting this to request clarification/verification, please?
1000 N / (0.25 * pi * (10 mm - 0.93194 * 1.5 mm)^2) ≈ 17.21 MPa
17 MPa seems rather low. If a nut covers 5-threads, the total stress is therefore just 3 MPa (17/5), translating to a maximum load acting on the steel nut (assuming proof strength of ~200 MPa) of approximately 10-tons.
10-tons seems a lot of weight before a loaded M10 nut will strip a bolt of its threads, which is why I'm posting this to request clarification/verification, please?