- #1
JordanHood
- 9
- 0
Homework Statement
A 5V battery rated at 1800mAh has a soucre resistance of 10 Ohms. What is the maximum power that can be extracted from the battery?
Homework Equations
The Attempt at a Solution
I understand that had the battery not had any source resistance then the power out would have been equal to Energy x Time giving us P=VIT, but i do no understand what to do when there is a source resistance. Do I calculate another current that is passing through the battery? using V=IR to get a current of 0.5A? If so then what does the 1800mAh mean? I have then tried putting this current into P=I^2R but this means I am totally ignoring one of the values in the question which means I can't be right
EDIT
Apologies I didnt realize this was a multiple choice question, the possible answers are
a) 625mW
b) 1.25mW
c) 2.5 mJ
d) 11.664 MJ
Last edited: