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mattmannmf
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A 630 gram rock is whirled on the end of a string 49 cm long which will break under a tension of 20 N.
a) What is the highest speed the rock can reach before the string breaks? (Neglect gravity.)
V=M/S
T- mg= ma
T-mg= m(v^2/r) solve for v
i get 2.188 m/s (which is wrong)
20-(630*9.8)= (630)(v^2/.49)
I converted 49 cm into .49 meters
help?
a) What is the highest speed the rock can reach before the string breaks? (Neglect gravity.)
V=M/S
T- mg= ma
T-mg= m(v^2/r) solve for v
i get 2.188 m/s (which is wrong)
20-(630*9.8)= (630)(v^2/.49)
I converted 49 cm into .49 meters
help?