- #1
TeslaPow
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I don't know how to integrate the Maxwell-Boltzmann distribution without approximation or help from Maple.
Given the Maxwell-Boltzmann distribution:
f(v) = 4*pi*[m/(2*pi*k*T)]^(3/2)*v^2*exp[(-m*v^2)/(2*k*T)]
Observe the appearance of the Boltzmann factor exp[(-m*v^2)/(2*k*T)] with E = 1/2(mv^2)
Assuming a fixed temperature and mass, one can simplify this equation:
f(v) = a*v^2*exp[-bv^2]
a = 4*pi*[m/(2*pi*k*T)]^(3/2)
b = m/(2*k*T)
In order to calculate the fraction of particles between two speeds v1 and v2, one should evaluate the definite integral:
∫f(v)dv
Here is an link to integral-tables, http://integral-table.com/
How would I solve this problem for let's say a certain amount of moles with hydrogen between two different velocities? Tor
Given the Maxwell-Boltzmann distribution:
f(v) = 4*pi*[m/(2*pi*k*T)]^(3/2)*v^2*exp[(-m*v^2)/(2*k*T)]
Observe the appearance of the Boltzmann factor exp[(-m*v^2)/(2*k*T)] with E = 1/2(mv^2)
Assuming a fixed temperature and mass, one can simplify this equation:
f(v) = a*v^2*exp[-bv^2]
a = 4*pi*[m/(2*pi*k*T)]^(3/2)
b = m/(2*k*T)
In order to calculate the fraction of particles between two speeds v1 and v2, one should evaluate the definite integral:
∫f(v)dv
Here is an link to integral-tables, http://integral-table.com/
How would I solve this problem for let's say a certain amount of moles with hydrogen between two different velocities? Tor