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[SOLVED] measure zero and differentiability
I proved in the preceding exercise the following characterization of measure zero:
"A subset E of R is of measure zero if and only if it has the following property:
(***) There exists a sequence [tex]J_k=]a_k,b_k[[/tex] such that every x in E belongs to an infinity of J_k and
[tex]\sum_{k=1}^{+\infty}(b_k-a_k)<+\infty[/tex]"
Now the question is the following:
Let E be of null measure and {J_k} be as above. Let also [tex]f_E:\mathbb{R}\rightarrow\mathbb{R}[/tex] be the increasing function defined by
[tex]f_E(x) = \sum_{k=1}^{+\infty}\lambda(]-\infty,x]\cap J_k)[/tex]
Show f is not differentiable at any point of E.
Differentiable iff the limit of the differential quotient exists and is bounded iff the left and right derivative are equal
Let h>0 and x0 be in E. I can write the right derivative and use the additivity of measure to simplify to
[tex]D_rf_E(x_0)=\lim_{h\rightarrow 0}\frac{\sum_{k=1}^{+\infty}\lambda([x,x+h]\cap J_k)}{h}[/tex]
then what? What difference does it make than x is in E? I mean, how does the fact that is belongs to an infinity of J_k comes in?
Homework Statement
I proved in the preceding exercise the following characterization of measure zero:
"A subset E of R is of measure zero if and only if it has the following property:
(***) There exists a sequence [tex]J_k=]a_k,b_k[[/tex] such that every x in E belongs to an infinity of J_k and
[tex]\sum_{k=1}^{+\infty}(b_k-a_k)<+\infty[/tex]"
Now the question is the following:
Let E be of null measure and {J_k} be as above. Let also [tex]f_E:\mathbb{R}\rightarrow\mathbb{R}[/tex] be the increasing function defined by
[tex]f_E(x) = \sum_{k=1}^{+\infty}\lambda(]-\infty,x]\cap J_k)[/tex]
Show f is not differentiable at any point of E.
Homework Equations
Differentiable iff the limit of the differential quotient exists and is bounded iff the left and right derivative are equal
The Attempt at a Solution
Let h>0 and x0 be in E. I can write the right derivative and use the additivity of measure to simplify to
[tex]D_rf_E(x_0)=\lim_{h\rightarrow 0}\frac{\sum_{k=1}^{+\infty}\lambda([x,x+h]\cap J_k)}{h}[/tex]
then what? What difference does it make than x is in E? I mean, how does the fact that is belongs to an infinity of J_k comes in?
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