Measuring distance using Ek and Ep?

[Clef]

measuring distance using Ek and Ep??!

okay, so the problem gives the following information
a car(1 tonne) is traveling at 75km/hr, up a hill. Assuming gravity is 9.8ms-2 , how far will the car travel?

so far I've done:
Ek= (.5 x m x v^2)
Ek= 36450000J

36450000=m x g x h
36450000=9800 x H
36450000/9800= H
H= 3719.38m

is this correct?

 

[Astronuc]

It would help if one shows the substitution of the values.

1/2 mv² = 0.5 * 1000 kg * (______ m/s)²? Make sure units are consistent.

 

[kyle8921]

As a scientist, it is important to always double-check your calculations and assumptions to ensure accuracy. In this case, your calculation for the kinetic energy (Ek) and potential energy (Ep) are correct. However, it is important to note that the given information does not specify the initial height of the car on the hill, so it is not accurate to assume that the potential energy is equal to the kinetic energy. Additionally, the given information does not specify the time frame in which the car is traveling, so it is not accurate to assume that the velocity (v) remains constant throughout the entire journey. To accurately measure distance using Ek and Ep, we would need more specific and relevant information such as the initial height and time frame. It is important to always consider all relevant factors and assumptions when conducting scientific calculations.