- #1
baddin
- 24
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Problem:
1. The pressure of a gas cell is measured with a mercurcy manometer. The mercury is 32.6 cm higher in the outside arm than in the arm connected to the gas cell. Calculate the gas pressure.
Relevant equations/given data
2. p(Pressure at depth h) = p(Pressure of atmosphere) + ρ(Density of liquid)*g(Gravitionational acceleration)*h
Pressure of atmosphere = 1atm = 101,300Pa. Density of mercury = 13,600kg/m^3
Attempted solution
3. p(gas) = p(Pressure of atmosphere) + ρ(Density of liquid)*g(Gravitionational acceleration)*h
p(gas) = 101,300 + (13600*9.8*0.326) = 144749.28Pa = 144.75kPa. I have the solution and it says the answer should be 149.5kPa. Have I done something wrong, or is the solution incorrect?
1. The pressure of a gas cell is measured with a mercurcy manometer. The mercury is 32.6 cm higher in the outside arm than in the arm connected to the gas cell. Calculate the gas pressure.
Relevant equations/given data
2. p(Pressure at depth h) = p(Pressure of atmosphere) + ρ(Density of liquid)*g(Gravitionational acceleration)*h
Pressure of atmosphere = 1atm = 101,300Pa. Density of mercury = 13,600kg/m^3
Attempted solution
3. p(gas) = p(Pressure of atmosphere) + ρ(Density of liquid)*g(Gravitionational acceleration)*h
p(gas) = 101,300 + (13600*9.8*0.326) = 144749.28Pa = 144.75kPa. I have the solution and it says the answer should be 149.5kPa. Have I done something wrong, or is the solution incorrect?