- #1
Griffy11
- 27
- 0
Hi everyone,
http://img372.imageshack.us/img372/6093/img009h.jpg
With the above, I really have no idea other than the standard s=d/t formula, but I doubt that has anything to do with it for a question worth 3 marks, and then looking at the two questions below, it'd make no sense.
The other idea I had was finding the total time, then the area under the graph for d, giving you s=d/t again, but using the method I just described. Then 25c would be answered by saying that finding instantaneous speed required a tangent drawn to the point etc, as opposed to the whole area under the curve.
Is the idea of finding d and t using area under the graph right, or am I way off?
Thanks for the help in advance.
http://img372.imageshack.us/img372/6093/img009h.jpg
With the above, I really have no idea other than the standard s=d/t formula, but I doubt that has anything to do with it for a question worth 3 marks, and then looking at the two questions below, it'd make no sense.
The other idea I had was finding the total time, then the area under the graph for d, giving you s=d/t again, but using the method I just described. Then 25c would be answered by saying that finding instantaneous speed required a tangent drawn to the point etc, as opposed to the whole area under the curve.
Is the idea of finding d and t using area under the graph right, or am I way off?
Thanks for the help in advance.
Last edited by a moderator: