- #1
RandyD123
- 66
- 7
- TL;DR Summary
- Referencing a YouTube Video
Does this video even make sense? And if so, is it right or wrong?
I suggest a forum search if you want more discussion. The topic has beaten to death numerous time here on PF.RandyD123 said:Does this video even make sense? And if so, is it right or wrong?
It is correct. The one way speed of light is indeed a convention.RandyD123 said:Summary:: Referencing a YouTube Video
Does this video even make sense? And if so, is it right or wrong?
Dale said:I wonder what the FLRW spacetime would look like under an anisotropic c synchronization.
The problem with any one-way measure, including the ones you cite, is that they assume that the speed of light is the same in both directions. Romer, for example, effectively looks at a distant clock (the Jovian moons) and attributes apparent rate variation solely to changing light travel time due to its changing distance. In a relativistic analysis, this turns out to mean that he assumed the Einstein clock synchronisation convention, which is to say that he assumed that the speed of light was isotropic. One could re-analyse the results using a non-isotropic synchronisation convention and get a different result.lerus said:As far as I understand, historicaly the very first measurement of speed of light - in 1676 by Olaus Roemer using Jupiter's satellites was a one-way measurement.
The second measurement of speed of light by James Bradley in 1726 using Stellar Aberration was also a one way measurement.
Just too ugly compared to the standard coordinates with the proper time of the comoving observers (comoving with the "cosmic substrate" or the rest frame of the cosmic microwave radiation).Dale said:I wonder what the FLRW spacetime would look like under an anisotropic c synchronization.
It is easy to set up experiments where the light path is one way. The issue is that all such experiments depend on some method of clock synchronization. Your assumption about clock synchronization determines the speed you get. In the case of Romer’s measurement he was using slow clock transport and assumed the isotropy of slow clock transport. This is equivalent to assuming the Einstein synchronization convention.lerus said:the very first measurement of speed of light - in 1676 by Olaus Roemer using Jupiter's satellites was a one-way measurement.
I’m skeptical. One could use a pulsed light source and two partially silvered mirrors separated by some distance. A single distant observer with a single clock could reside equally distant from each mirror. The distant observer would see two pulses separated by the time of flight of the pulse between the mirrors. The source is moved and the pulse sent along the reverse direction.Dale said:It is easy to set up experiments where the light path is one way. The issue is that all such experiments depend on some method of clock synchronization.
Are you basically suggesting sending light pulses along one edge and the other two edges of a closed triangular path? That's a two-way measurement.Paul Colby said:I’m skeptical. One could use a pulsed light source and two partially silvered mirrors separated by some distance. A single distant observer with a single clock could reside equally distant from each mirror. The distant observer would see two pulses separated by the time of flight of the pulse between the mirrors. The source is moved and the pulse sent along the reverse direction.
How so? Only one observer and only one clock.Ibix said:sending light pulses along one edge and the other two edges of a closed triangular path? That's a two-way measurement.
This is assumes already that the one way speed of light is isotropic.Paul Colby said:I’m skeptical. One could use a pulsed light source and two partially silvered mirrors separated by some distance. A single distant observer with a single clock could reside equally distant from each mirror. The distant observer would see two pulses separated by the time of flight of the pulse between the mirrors. The source is moved and the pulse sent along the reverse direction.
That is actually the identifying feature of a two way measurement. Actual one way measurements require two clocks so they require an assumption about simultaneity.Paul Colby said:How so? Only one observer and only one clock.
Only if one defines a partiality reflective mirror as a clock in this case.Dale said:That is actually the identifying feature of a two way measurement. Actual one way measurements require two clocks.
This doesn’t work. In the limit the directions become arbitrarily close but the distance becomes arbitrarily long. The time difference from any anisotropy in the speed of light decreases as the directions become close, but it increases as the distance increases. The two effects together mean that even in the limit of a distant observer the anisotropy assumption is still non-negligible.Paul Colby said:In the limit the observer is infinitely far away the path directions become identical.
It has nothing to do with that. The mirror isn’t a clock. The experiment is a two way experiment because the direction of the light is changed, a single clock is used, and the calculation of the speed of light depends on an assumption about the isotropy of the speed of light. All of those are characteristics of two way measurements.Paul Colby said:Only if one defines a partiality reflective mirror as a clock in this case.
There is a further condition that you have neglected. That is that the function ##c(\theta)## must have the two way speed of light equal to ##c##. In other words, for any constant path (in an inertial frame) of length ##s##, the time for light to traverse that path forward plus the time to traverse the same path backward is ##2s/c##. This is required because the two-way speed of light is measurable and is ##c##.Paul Colby said:We make the following further assumptions that c(θ) is a real single valued analytic function of θ.
Any such choices are ruled out by the two way speed of light condition.Paul Colby said:So, my question / observation is; will ##\Delta_A = \Delta_B## for all ##c(\theta)##? Clearly not since there are choices which make ##\pm(\Delta_{2D} - \Delta_{1D})## negligible while ##\Delta_{12} - \Delta_{21}## is not.
What is the origin of this requirement?Dale said:There is a further condition that you have neglected.
Okay, tryDale said:Any such choices are ruled out by the two way speed of light condition.
That's not the requirement. For example, one requirement is:Paul Colby said:This function meets the requirement, ##c(\theta)+c(\theta+\pi)=2c##, yet yields ##\Delta_A \ne \Delta_B##.
Good catch.Sagittarius A-Star said:That's not the requirement. For example, one requirement is:
No, you want$$Paul Colby said:So, If I produce a function ##c(\theta)+c(\theta+\pi) = 2c## which yield ##\Delta_A \ne \Delta_B##. then what?
Yes, that holds exactly for ##c(\theta)## given in #25.DrGreg said:No, you want$$
\frac{1}{c(\theta)} + \frac{1}{c(\theta+\pi)} = \frac{2}{c}
$$
The origin of the requirement is experiment. Whatever function we choose for ##c(\theta)## must be compatible with experiment. Experimentally, if we bounce light around any closed path we measure ##\Delta t= s/c## where ##s## is the path length and ##\Delta t## is the time between emission and reception.Paul Colby said:What is the origin of this requirement?
You are correct. I gave a weaker statement than the actual experimental constraint. I thought that the weaker constraint I stated implied the experimental constraint, but as you have shown it does not. My apologies.Paul Colby said:Okay, try
##c(\theta) = c + \epsilon\cos^7\theta##
This function meets the requirement, ##c(\theta)+c(\theta+\pi)=2c##, yet yields ##\Delta_A \ne \Delta_B##.
Well, we need to pick a set of requirements and stick with them. I follow that ##\Delta_{1D}+\Delta_{D1}## must average but lose it on ##\Delta_{2D}+\Delta_{D1}##. I can’t reproduce your result.Dale said:The origin of the requirement is experiment. Whatever function we choose for ##c(\theta)## must be compatible with experiment. Experimentally, if we bounce light around any closed path we measure ##\Delta t= s c##.
You are correct. I gave a weaker statement than the actual experimental constraint. I thought that the weaker constraint I stated implied the experimental constraint, but as you have shown it does not. My apologies.
With the correct constraint it is clear that ##\Delta_A=\Delta_B## by direct calculation.
##\Delta_A=\Delta_{12}+\Delta_{2D}-\Delta_{1D}##
##\Delta_A=\Delta_{12}+\Delta_{2D}-\Delta_{1D}+\Delta_{D1}-\Delta_{D1}##
##\Delta_A=\Delta_{12}+\Delta_{2D}+ \Delta_{D1}-(\Delta_{1D}+ \Delta_{D1})##
##\Delta_A=(2R+2W-4W)/c##
And similarly with ##\Delta_B##
Since the time around any closed loop equals the length (perimeter) of the loop divided by ##c## we have ##\Delta_{12}+\Delta_{2D}+ \Delta_{D1}=(2R+2W)/c## and ##\Delta_{1D}+ \Delta_{D1}=4W/c##Paul Colby said:I follow that ##\Delta_{1D}+\Delta_{D1}## must average but lose it on ##\Delta_{2D}+\Delta_{D1}##. I can’t reproduce your result.
##\Delta_{D1}-\Delta_{D1}=0## so we are free to add it to your original expression for ##\Delta_A##Paul Colby said:also, ##\Delta_{D1}## and the like don’t appear in the measurement.
Yeah, I don’t accept this as a requirement. It may well be a valid result given the usual velocity anisotropy but I believe it need not hold for those being considered here.Dale said:Since the time around any closed loop equals the length (perimeter) of the loop divided by c we have
You are not free to reject it. It is required by experiment. Any convention that does not satisfy this requirement is experimentally falsified.Paul Colby said:Yeah, I don’t accept this as a requirement. It may well be a valid result given the usual velocity anisotropy but I believe it need not hold for those being considered here.
Fine, which experiment.Dale said:You are not free to reject it. It is required by experiment. Any convention that does not satisfy this requirement is experimentally falsified.
Any non-rotating ring interferometer experimentPaul Colby said:Fine, which experiment.
Like all things these are done to finite precision. So, we’ve established the point I was trying to make which is the class of acceptable ##c(\theta)## is really rather narrow. One is restricted to ones that are not measurable. The ones I proposed are measurable and therefore disallowed for some value of the paramete ##\epsilon##.Dale said:Any non-rotating ring interferometer experiment