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zing478
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Homework Statement
A wavelength measurement gives Lambda= 6000 x 10^-10m with an accuracy of one part in a million. What is the minimum uncertainty in the position of the photon?
Homework Equations
deltaP*deltaX > h/4pi
p = h/lambda
The Attempt at a Solution
In order to solve, I know deltaP has to be expressed in terms of deltaLambda. Delta lambda is (6000 x 10^-10)(1 x 10^-6) = 6 x 10^-13.
delta P = dp/dLambda * deltaLambda
I'm not sure how to solve this relationship to get an expression for deltaLambda, to plug back into the original
deltaX > h/(4pi)(deltaP)
Once I get the expression for momentum in terms of lambda, I think I just sub it back in and solve for deltaX.
Any help? or have I done anything wrong so far?