- #1
Mark Sullivan
- 23
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A bicyclist applies varied force and velocity on their pedals as it goes around one revolution. The power distribution over one revolution is like two waves with the higher power being made on the downstrokes. The push through the bottom/top produces the lowest power. The question is does measuring velocity 1 per revolution and averaging the force gives you an accurate measurement or a weighted average velocity matched to force every quarter rotation gives you a better power reading per revolution?
One problem with the second is the timing of those quarter sampling in a varied force velocity application can give you a range of different results.
A simplified example:
1, 0.25sec, 62rpm, 10 torque units (e.g. left leg across top of stroke)
2, 0.25sec, 58rpm, 50 torque units (left leg downstroke)
3, 0.25sec, 62rpm, 10 torque units (right leg across top of stroke)
4, 0.25sec, 58rpm, 50 torque units (right leg downstroke)
Average velocity = 60rpm
Magnet/reed switch calculation:
Average torque = (10 + 50 + 10 + 50) / 4 = 30TU
Power = 60rpm x 30TU = 1,800 power units
However, if you calculate the power for each time sample (hence account for the different velocity recorded during each sample), then:
Power = (62x10 + 58x50 + 62x10 + 58x50) / 4 = 1,760 power units
But the timing of sampling is arbitrary and it could measure have started measuring .135 sec earlier in .25 sec samplings so you could get.
Power= (60x30 + 60x30 + 60x30 + 60x30)/4 = 1,800 power units
I you moved the .25 sec sampling from this point to the first .25 sec sampling you can get power units from 1,760 to 1,800.
Which is the correct measuring of power per revolution? and why?
Thanks
One problem with the second is the timing of those quarter sampling in a varied force velocity application can give you a range of different results.
A simplified example:
1, 0.25sec, 62rpm, 10 torque units (e.g. left leg across top of stroke)
2, 0.25sec, 58rpm, 50 torque units (left leg downstroke)
3, 0.25sec, 62rpm, 10 torque units (right leg across top of stroke)
4, 0.25sec, 58rpm, 50 torque units (right leg downstroke)
Average velocity = 60rpm
Magnet/reed switch calculation:
Average torque = (10 + 50 + 10 + 50) / 4 = 30TU
Power = 60rpm x 30TU = 1,800 power units
However, if you calculate the power for each time sample (hence account for the different velocity recorded during each sample), then:
Power = (62x10 + 58x50 + 62x10 + 58x50) / 4 = 1,760 power units
But the timing of sampling is arbitrary and it could measure have started measuring .135 sec earlier in .25 sec samplings so you could get.
Power= (60x30 + 60x30 + 60x30 + 60x30)/4 = 1,800 power units
I you moved the .25 sec sampling from this point to the first .25 sec sampling you can get power units from 1,760 to 1,800.
Which is the correct measuring of power per revolution? and why?
Thanks