Mechanics problem: A Weight and a Mass Suspended from a String

  • #1
smnjech
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I have difficulty solving this problem.

A homogeneous sphere of weight G, radius R is suspended at location 0 together with a weight of weight P in the manner indicated in Fig. 2.5. Determine the angles and the force F acting on the sphere from the hinge of the weight P.

The thing that makes me confused is that in the solution of the problem stated in the book, the angle of α/2 appears and I do not know why.
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  • #2
You need to show your work. We can't give help until you show an effort.
 
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  • #3
phinds said:
You need to show your work. We can't give help until you show an effort.
The main idea that I started with was that there has to be static equilibrium, so the sum of all forces acting on a sphere must give zero. I decomposed the forces into x and y components and for the x component I came up with Tsin(φ)=Fcos(α) and for y component Fsin(α)+G=Tcos(φ). But when I later looked at the solution there was α/2 instead of α and I dont umderstand why.
 
  • #4
You need the torque equation with respect to the point O to the whole system and a lot of geometry.
 
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  • #5
smnjech said:
The main idea that I started with was that there has to be static equilibrium, so the sum of all forces acting on a sphere must give zero. I decomposed the forces into x and y components and for the x component I came up with Tsin(φ)=Fcos(α) and for y component Fsin(α)+G=Tcos(φ). But when I later looked at the solution there was α/2 instead of α and I dont umderstand why.
I am trying to decode your equations to figure out why you think they apply.

So ##F## is the tension in the right hand cord supporting weight ##P##. You seem to think that this force is applied at an angle ##\alpha## below the horizontal to the sphere.

Can you identify the two angles where the cord meets the sphere above its equator and then departs from the sphere at its equator? What is the average of those two angles?

At what angle, on average, does the contact force of cord on sphere act?
With what net force does it act?
 
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  • #6
smnjech said:
The thing that makes me confused is that in the solution of the problem stated in the book, the angle of α/2 appears and I do not know why.
Show us the expression in which ##\alpha /2## appears.
 
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  • #7
Is ##\ell## a rod that connected to the sphere perpendicular and such that they both form a rigid body?
 
  • #8
wrobel said:
Is ##\ell## a rod that connected to the sphere perpendicular and such that they both form a rigid body?
Yes it is.
 
  • #9
Then it is indeed a simple application of the torque equation.
 
  • #10
Welcome, @smnjech !

Could you identify the terms T and F in the shown equations?

Consider that the string is always wrapping the sphere, for any position.
The force that the string applies on the sphere is always pointing to its center (perpendicular direction to the tangent line formed by both sides of the string).

What is the angle that each of those sides symmetrically form with that tangent line?

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  • #11
Lnewqban said:
The force that the string applies on the sphere is always pointing to its center
not always but in the absence of friction
 

FAQ: Mechanics problem: A Weight and a Mass Suspended from a String

What is the difference between weight and mass in this problem?

Weight is the force exerted by gravity on an object, calculated as the product of the object's mass and the acceleration due to gravity (W = mg). Mass is the measure of the amount of matter in an object and is usually measured in kilograms or grams.

How do you calculate the tension in the string?

The tension in the string can be calculated by analyzing the forces acting on the mass. If the system is in equilibrium, the tension (T) in the string will be equal to the weight of the mass (T = mg). If the mass is accelerating, you need to account for the net force and use Newton's second law (T = mg ± ma) depending on the direction of the acceleration.

What happens to the tension if a second mass is added to the string?

If a second mass is added to the string, the tension will depend on the sum of the weights of both masses. If the system is in equilibrium, the tension will be T = (m1 + m2)g. If the system is accelerating, you need to consider the net force and use Newton's second law accordingly.

How does the angle of the string affect the tension?

When the string makes an angle with the vertical, the tension in the string has both vertical and horizontal components. The vertical component of the tension must balance the weight of the mass. If θ is the angle with the vertical, the tension can be calculated using T = mg / cos(θ).

How do you account for the mass of the string in calculations?

If the string has a significant mass, it will contribute to the overall weight and affect the tension distribution along the string. The tension will vary along the length of the string, being highest at the point where the string is attached. To account for the mass of the string, you need to integrate the tension considering the linear mass density of the string and the gravitational force acting on each segment.

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