- #1
JamieB2
- 1
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Homework Statement
http://img213.imageshack.us/img213/1681/question1su9.png
Apologies for the scrappy diagram. My MS Paint skills aren't amazing.
Homework Equations
Personally, I'm not too sure. This question (I think) involves things that I haven't studied, I tried to do a little research into it on the Internet but it didn't help too much in the end. All I could really think of was
sec [tex]\theta[/tex] = 1/cos[tex]\theta[/tex]
tan^2 [tex]\theta[/tex] + 1 = sec^2 [tex]\theta[/tex]
sin^2 [tex]\theta[/tex] + cos^2 [tex]\theta[/tex] = 1
tan^2 [tex]\theta[/tex] = (1 - cos2[tex]\theta[/tex])/(1 + cos2[tex]\theta[/tex])
cos2[tex]\theta[/tex] = (2cos^2[tex]\theta[/tex] -1)
And maybe Pythagoras' theorem
The Attempt at a Solution
(Note; for ease of writing on paper, I replaced [tex]\alpha[/tex] with [tex]\theta[/tex], because, pathetic as it sounds, I don't like writing [tex]\alpha[/tex])
A bit of a mess, one of my lines of work went;
49sin^2[tex]\theta[/tex] + 49cos[tex]\theta[/tex] = 2401 = 49^2
sin^2 [tex]\theta[/tex] + cos^2 [tex]\theta[/tex] = 1
Divide all by cos^2[tex]\theta[/tex]
(sin^2[tex]\theta[/tex])/(cos^2[tex]\theta[/tex]) + 1 = sec^2[tex]\theta[/tex]
tan^2[tex]\theta[/tex] + 1 = sec^2[tex]\theta[/tex]
Which, obviously, doesn't help towards my answer.
What I'm most interested in is a kind of kick start, if I knew what kind of thing I'm supposed to do, I'd maybe be able to do the question myself, but I honestly do not know where to start.
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