- #1
JohanL
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Problem:
A homogeneous cylinder of mass M and radius R can roll without
slipping on a horisontal table. One end of the cylinder reaches a tiny
bit out over the edge of the table. At a point of the pheriphery of the
end surface of the cylinder, a homogeneous rod is attached to the
cylinder by a frictionless joint. The rod has mass m and length l. Find
Lagrange's equations for the generalised coordinates phi (angle in the cylinder) and theta (rod's angle)
according to the figure, and determine the frequences of the principal
modes of small oscillations. (Principal frequences = roots of
characteristic equation.)
___________________________
I have a attached a figure.
With
[tex]T = 1/4MR^2 \dot{\phi}^2 + 1/6ml^2 \dot{\theta}^2[/tex]
[tex]U=mg[R(1-cos\phi)+l/2(1-cos\theta)][/tex]
[tex]L=T-U[/tex]
I get the equation of motions
[tex]\ddot{\phi}=\frac{2mg}{MR}\phi[/tex]
[tex]\ddot{\theta}=\frac{3g}{2l}\theta[/tex]
which is the correct answer except a factor 1/3 in the equation for phi.
But it feels like i have done some big misstakes computing T.
I haven't included that the rod is attached to the cylinder. And I am not sure how to do this.
And i haven't included the the cylinder is rolling ?!?
Any ideas?
A homogeneous cylinder of mass M and radius R can roll without
slipping on a horisontal table. One end of the cylinder reaches a tiny
bit out over the edge of the table. At a point of the pheriphery of the
end surface of the cylinder, a homogeneous rod is attached to the
cylinder by a frictionless joint. The rod has mass m and length l. Find
Lagrange's equations for the generalised coordinates phi (angle in the cylinder) and theta (rod's angle)
according to the figure, and determine the frequences of the principal
modes of small oscillations. (Principal frequences = roots of
characteristic equation.)
___________________________
I have a attached a figure.
With
[tex]T = 1/4MR^2 \dot{\phi}^2 + 1/6ml^2 \dot{\theta}^2[/tex]
[tex]U=mg[R(1-cos\phi)+l/2(1-cos\theta)][/tex]
[tex]L=T-U[/tex]
I get the equation of motions
[tex]\ddot{\phi}=\frac{2mg}{MR}\phi[/tex]
[tex]\ddot{\theta}=\frac{3g}{2l}\theta[/tex]
which is the correct answer except a factor 1/3 in the equation for phi.
But it feels like i have done some big misstakes computing T.
I haven't included that the rod is attached to the cylinder. And I am not sure how to do this.
And i haven't included the the cylinder is rolling ?!?
Any ideas?
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