Mechanisms of Supercooling and Supersaturation

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In summary, supercooling is when a liquid remains in a liquid state below its normal freezing point, while supersaturation is when a solution contains more solute than it can normally hold. The mechanisms for these processes vary, but can include adding nucleating agents, changing pressure or concentration, or increasing solute concentration. Supercooling and supersaturation have numerous applications in everyday life, such as producing amorphous pharmaceuticals and flash freezing food. However, they can also be hazardous if not properly controlled, potentially causing explosions or environmental harm. Scientists study and manipulate these processes using techniques like differential scanning calorimetry and X-ray diffraction, and by controlling factors such as pressure, temperature, and concentration.
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I have a couple of questions:

The homogeneous freezing temperature of water is listed at -42C. However, from the equations formulated to find critical radius here, I did not see any factors which restricts the homogeneous nucleation temperature to a certain value. How is the homogeneous nucleation temperature defined? I can see how the probability of a nuclei of critical radius increases with decreasing temperatures. However, in the absence of heterogeneous nucleation sites, would a block of water left at say -20C never freeze, or would it eventually freeze after a very long time? Microscopically how is a solid nucleus formed?

In the same Wikipedia article, I did not understand this statement:
Supercooling brings about supersaturation, the driving force for nucleation. Supersaturation occurs when the pressure in the newly formed solid is less than the liquid pressure
what is meant by solid and liquid pressure, and since they are different, can phase change be considered isobaric?

How is supersaturation achieved? I think one way is to lower the temperature of some water vapour inside an enclosed container with no nucleation sites. Is it possible to generate a supersaturated system by evaporation, such that water continue to evaporate even when P > P_sat(T_system)?

Similar to the above question, if I have liquid water in equilibrium with its vapour (P_vapour = P_sat(T)) inside an closed system with no nucleation sites at temperature T, if I lower the temperature, does the system supersaturate, or does vapour begin condensing?

Thank you
 
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for your help!The homogeneous nucleation temperature is usually defined as the temperature at which the probability of a nucleus of critical radius is great enough to allow for spontaneous freezing. The probability increases with decreasing temperatures, so it is usually assumed that the homogeneous nucleation temperature is -42C. However, this is just an approximation and the exact temperature could be different depending on the conditions.Solid pressure is the pressure exerted by the solid material that forms the nucleus of a crystal. It is the pressure inside the solid at the time of nucleation. Liquid pressure is the pressure exerted by the liquid material that surrounds the solid nucleus. It is the pressure of the liquid at the time of nucleation. Phase change can be considered isobaric if the pressure in the newly formed solid is equal to the liquid pressure. Supersaturation is achieved by cooling a gas or liquid below its saturation temperature. When the temperature is lowered, the vapor pressure drops below the atmospheric pressure, creating a supersaturated state. It is also possible to generate a supersaturated system by evaporation, as long as the pressure stays below the saturation vapor pressure at the given temperature. If you lower the temperature of liquid water in equilibrium with its vapor, the vapor pressure will drop below the atmospheric pressure, resulting in supersaturation. If there are no nucleation sites present, the water will remain in a supersaturated state until a nucleus forms, at which point it will begin to condense.
 

FAQ: Mechanisms of Supercooling and Supersaturation

What is supercooling and supersaturation?

Supercooling is the process in which a liquid remains in a liquid state at a temperature below its normal freezing point. Supersaturation is the process in which a solution contains more solute than it can normally hold at a given temperature and pressure.

What are the mechanisms of supercooling and supersaturation?

The mechanisms of supercooling and supersaturation vary depending on the substance and conditions. Some common mechanisms include adding a nucleating agent to induce crystal formation, decreasing pressure to lower the freezing point, and increasing the concentration of solutes to create supersaturation.

What are the applications of supercooling and supersaturation in everyday life?

Supercooling and supersaturation have various applications in daily life. Examples include the production of amorphous pharmaceuticals, the preservation of food through flash freezing, and the creation of smooth and creamy ice cream.

What are the potential hazards of supercooling and supersaturation?

Supercooling and supersaturation can be hazardous if not properly controlled. In some cases, sudden crystallization can occur, leading to explosions or damage to equipment. In addition, supersaturated solutions can be unstable and may crystallize rapidly, causing potential harm to the surrounding environment.

How do scientists study and manipulate supercooling and supersaturation?

Scientists use various techniques to study and manipulate supercooling and supersaturation, such as differential scanning calorimetry, X-ray diffraction, and microscopy. They also use different methods to control these processes, such as changing pressure, temperature, and concentration, or introducing nucleating agents and seeding crystals.

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