Merry-go-round at rest, inertia, kid running on it problem.

In summary, the question asks for the angular speed of a system consisting of a stationary merry-go-round and a 45kg child running at 3.50m/s tangential to the rim. After the child jumps off, the entire system begins to rotate. The solution involves using conservation of angular momentum and does not require calculating acceleration or torque.
  • #1
1barcafan
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Homework Statement


a 45kg child runs with a speed of 3.50m/s tangential to the rim of a stationary merry-go-round that has a momentum of inertia of 555 kg m^2, and a radius of 2.45m. when the child jumps off, the entire system begins to rotate. what is the angular speed of the system?



Homework Equations





The Attempt at a Solution


i found the circumference of the merry-go-round. assuming initial displacement is 0, final is 15.39 (circumfrence), initial velocity is 3.50m/s, and final velocity is 0, i found time to be 8.79s and acceleration to be -.40 m/s^2. using that acceleration and the mass of the child i found force, then using that force and distance i found torque. (i wasn't even taught torque, i just watched a youtube video on it and it seemed appropriate to incorporate it into this problem). once i did all of this, i just got stuck, I've never had a problem that asked for angular speed before so this is just something completely foreign.
 
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  • #2
Hi 1barcafan! :smile:
1barcafan said:
a 45kg child runs with a speed of 3.50m/s tangential to the rim of a stationary merry-go-round that has a momentum of inertia of 555 kg m^2, and a radius of 2.45m. when the child jumps off, the entire system begins to rotate. what is the angular speed of the system?

I don't understand the question. :confused:

Are you sure it doesn't say that the when the child jumps onto the merry-go-round, the entire system (ie merry-go-round plus child) begins to rotate?

Anyway, this has nothing to do with acceleration (or torque ).

This is a collision, so use conservation of angular momentum. :wink:
 

FAQ: Merry-go-round at rest, inertia, kid running on it problem.

What is the concept of inertia and how does it relate to a merry-go-round at rest?

Inertia is the property of an object to resist a change in its state of motion. In the case of a merry-go-round at rest, the inertia of the object causes it to remain stationary unless acted upon by an external force.

How does the motion of a kid running on a merry-go-round affect its inertia?

When a kid runs on a merry-go-round, their movement adds an external force to the object. This force acts in the direction of the kid's motion, causing the merry-go-round to spin in the same direction. However, the inertia of the object resists this change in motion, causing the merry-go-round to continue spinning even after the kid stops running.

Why does the kid on the merry-go-round feel like they are being pushed outward?

This is due to the centrifugal force, which is the outward force experienced by an object in circular motion. As the merry-go-round spins, the kid's body wants to continue moving in a straight line, but the force of the merry-go-round's rotation pushes them outward.

Can the speed of the merry-go-round affect the kid's ability to run on it?

Yes, the speed of the merry-go-round can affect the kid's ability to run on it. As the speed of the merry-go-round increases, so does the centrifugal force pushing the kid outward. This can make it harder for the kid to maintain their balance and continue running on the moving object.

How does the concept of inertia apply to other objects in motion?

Inertia applies to all objects in motion, not just a merry-go-round. The amount of inertia an object has depends on its mass - the greater the mass, the greater the inertia. This means that objects with larger masses require more force to change their state of motion compared to objects with smaller masses.

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