Mesh Analysis: Solving for I1 with Loop Equations

In summary: I didn't know how to express it at the beginning but that's what I had in mindarctan -1 is the same as arctan 0. It's not directly related to what you're doing.Arctan can't "see" the two negative signs of its argument; they cancel when you do the division. It's up to you, the user, to make sure that the angle ends up in the right quadrant. I'm sure you covered the domain and range of the trig functions in one of your previous courses dealing with trigonometry.As an alternative to arctan, if your calculator has an atan2(y,x) function, then it takes both arguments separately and always returns the
  • #36
shaltera said:
0.052-j0.764

What is that? If it's i2 it doesn't look right. Show your steps.
 
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  • #37
i1=0.093<-98.86

I converted polar form to complex numbers for i1
-0.0143+j0.091 then I entered in

i2=--4i1-j10/25
i2=-4(-0.0143+j0.091)-j0.4=0.052-j0.364-j0.4=0.052-j0.764
i2=0.052-j0.764=sqr(0.0522+(-0.764)2)tan -1(-(0.764/0.052)=0.765<-86.106
 
  • #38
shaltera said:
i1=0.093<-98.86

I converted polar form to complex numbers for i1
-0.0143+j0.091 then I entered in
Should be: -0.0143 - j0.0911
Check your conversion. You should note that an angle of -98.86° places it in the third quadrant, so both terms must be negative.

i2=--4i1-j10/25
i2=-4(-0.0143+j0.091)-j0.4=0.052-j0.364-j0.4=0.052-j0.764
i2=0.052-j0.764=sqr(0.0522+(-0.764)2)tan -1(-(0.764/0.052)=0.765<-86.106
 
  • #39
I calculated with Matlab

for I1=-0.0143-0.0911i=0.0922<-98.9040
for I2= 0.0571-0.0356i=0.0673<-31.9553

I don't get it why we have to calculate by hand?
 
  • #40
Can I use Matlab for my assessment?

a=[47+100j 100j;100j 25j]
b=[12;10]
i=a\b

then magn=abs(i)
and then the angle
angle(i)*180/pi

Why do we have to calculate by hand?I'm not living in 20 century
 
  • #41
shaltera said:
I calculated with Matlab

for I1=-0.0143-0.0911i=0.0922<-98.9040
for I2= 0.0571-0.0356i=0.0673<-31.9553

I don't get it why we have to calculate by hand?

Yes, those values look good. As to why you have to calculate by hand, I can only presume that there are "pedagogical reasons"; You'll have to ask your instructor.
 
  • #42
shaltera said:
Can I use Matlab for my assessment?

a=[47+100j 100j;100j 25j]
b=[12;10]
i=a\b

then magn=abs(i)
and then the angle
angle(i)*180/pi

Why do we have to calculate by hand?I'm not living in 20 century

Who says you have to calculate by hand? Your instructor? Many instructors will require you to calculate by hand for a while so that you learn how complex arithmetic works. But, after a while, you should be able to use modern software or calculators.
 
  • #43
Apart of Matlab, I do not have a calculator with atan2 function.I was looking for a formula to convert polar to rectangular form but all examples are with positive values
 
  • #44
Many calculators have built-in polar to rectangular (and back) functions. They will accomplish the same thing.
 

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