- #1
GravityX
- 19
- 1
- Homework Statement
- Calculate the energy of the various segments, taking into account the work done by the force F during expansion, when it expands.
- Relevant Equations
- none
Hi
It is about a DNA strand on which there are always two segments, the segment ##A##, which is folded and has the length ##l_A## and the unfolded segment ##B##, which has ##l_B+\lambda##. Here is a section of the DNA
There is now, as shown in the picture, a force ##F## pulling on the strand, to unfold a segment A the energy ##\epsilon## (not dependent on the force ##F##) is needed.
The first task is then:
Determine the energies of the two states of a segment
taking into account the work done by the force ##F## during expansion.
I have now thought of the following: The folded segments have the energy ##\epsilon_A=0## the force now does positive work, so the energy for these segments corresponds to ##\epsilon_{AF}=F*a##.
The unfolded segments have the energy ##\epsilon_B=epsilon##, now add the energy from the force ##F## so ##\epsilon_{BF}=\epsilon+F*a##.
But I think that the energy is unfortunately wrong, in problem 3 you are supposed to calculate the expected length l for an unfolded segment, so ##\langle l \rangle## the result there is ##\langle l \rangle=l_A+\frac{\lambda}{1+e^{\beta(\epsilon-F\lambda)}}##
Before that you had to get the partition function and the probability, I think you need this probability for the expected value.
With the partition function with ##e^{-\beta \epsilon_{BF}}=e^{-\beta (\epsilon_B+Fa)}##
and the probability with ##P=\frac{1}{Z}e^{-\beta (\epsilon+Fa)}## with ##Z=e^{-\beta (\epsilon+Fa)}+e^{-\beta Fa}## is then ##P=\frac{1}{e^{\beta \epsilon}+1}##
I would now have calculated the expectation value with ##l*P##, so ##\langle l \rangle=l_A+\lambda*P##, but unfortunately I don't get the result I'm looking for.
Is my energy simply not right or have I miscalculated somewhere?
It is about a DNA strand on which there are always two segments, the segment ##A##, which is folded and has the length ##l_A## and the unfolded segment ##B##, which has ##l_B+\lambda##. Here is a section of the DNA
There is now, as shown in the picture, a force ##F## pulling on the strand, to unfold a segment A the energy ##\epsilon## (not dependent on the force ##F##) is needed.
The first task is then:
Determine the energies of the two states of a segment
taking into account the work done by the force ##F## during expansion.
I have now thought of the following: The folded segments have the energy ##\epsilon_A=0## the force now does positive work, so the energy for these segments corresponds to ##\epsilon_{AF}=F*a##.
The unfolded segments have the energy ##\epsilon_B=epsilon##, now add the energy from the force ##F## so ##\epsilon_{BF}=\epsilon+F*a##.
But I think that the energy is unfortunately wrong, in problem 3 you are supposed to calculate the expected length l for an unfolded segment, so ##\langle l \rangle## the result there is ##\langle l \rangle=l_A+\frac{\lambda}{1+e^{\beta(\epsilon-F\lambda)}}##
Before that you had to get the partition function and the probability, I think you need this probability for the expected value.
With the partition function with ##e^{-\beta \epsilon_{BF}}=e^{-\beta (\epsilon_B+Fa)}##
and the probability with ##P=\frac{1}{Z}e^{-\beta (\epsilon+Fa)}## with ##Z=e^{-\beta (\epsilon+Fa)}+e^{-\beta Fa}## is then ##P=\frac{1}{e^{\beta \epsilon}+1}##
I would now have calculated the expectation value with ##l*P##, so ##\langle l \rangle=l_A+\lambda*P##, but unfortunately I don't get the result I'm looking for.
Is my energy simply not right or have I miscalculated somewhere?
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