I Microring resonator matrix

AI Thread Summary
The discussion centers on the mathematical representation of a simple ring resonator with a bus waveguide, specifically questioning the presence of the conjugate terms -k* and t* in the matrix equation. The original poster expresses confusion about why these terms are used instead of k and t, suggesting that the conjugation relates to the phase of the circulating mode. Several referenced papers are noted for lacking explanations regarding the conjugate terms, as they either utilize the matrix without clarification or present alternative forms without conjugation. The need for further investigation into the mathematical derivation and its implications is emphasized. Overall, the conversation highlights a gap in the literature regarding the theoretical basis for the matrix representation in ring resonators.
Rampart123
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TL;DR Summary
Explaining the matrix elements.
Hello everyone,
1713121310430.png

A simple ring resonator with a bus waveguide is described by:
$$ \begin{pmatrix} E_{t1}\\ E_{t2} \end{pmatrix} =
\begin{pmatrix} t & k\\ -k^* & t^* \end{pmatrix}
\begin{pmatrix} E_{i1}\\ E_{i2} \end{pmatrix} $$

I do not understand though why we have -k* and t*? Shouldn't they be also k and t?

I think the conjugation has to do with the phase of the circulating mode?

Thank you in advance!
 
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Rampart123 said:
TL;DR Summary: Explaining the matrix elements.

Hello everyone,

A simple ring resonator with a bus waveguide is described by:
$$ \begin{pmatrix} E_{t1}\\ E_{t2} \end{pmatrix} =
\begin{pmatrix} t & k\\ -k^* & t^* \end{pmatrix}
\begin{pmatrix} E_{i1}\\ E_{i2} \end{pmatrix} $$

I do not understand though why we have -k* and t*? Shouldn't they be also k and t?

I think the conjugation has to do with the phase of the circulating mode?

Thank you in advance!
The derivation appears in several papers, unfortunately some of these references are behind a paywall:

https://opg.optica.org/oe/fulltext.cfm?uri=oe-12-1-90&id=78458
https://digital-library.theiet.org/content/journals/10.1049/el_20000340
https://www.researchgate.net/public...GFnZSI6Il9kaXJlY3QiLCJwYWdlIjoiX2RpcmVjdCJ9fQ
 
Andy Resnick said:
Thank you for the reply. However, it seems to me that it is not explained in neither of these 3 papers that you mentioned.
In the first paper: It just uses the matrix but does not explain why we have the conjugate
In the second paper: The same as in the first.
In the third paper: The matrix does not have any conjugation, but rather the matrix consists of only t and k, which was also the question of mine.

Why it is
$$ \begin{pmatrix} E_{t1}\\ E_{t2} \end{pmatrix} =
\begin{pmatrix} t & k\\ -k^* & t^* \end{pmatrix}
\begin{pmatrix} E_{i1}\\ E_{i2} \end{pmatrix} $$ and not

$$ \begin{pmatrix} E_{t1}\\ E_{t2} \end{pmatrix} =
\begin{pmatrix} t & k\\ k & t \end{pmatrix}
\begin{pmatrix} E_{i1}\\ E_{i2} \end{pmatrix} $$

Most articles do not explain, they just use the matrix that they found in a book and then do some calculations.
 
Rampart123 said:
Thank you for the reply. However, it seems to me that it is not explained in neither of these 3 papers that you mentioned.
In the first paper: It just uses the matrix but does not explain why we have the conjugate
In the second paper: The same as in the first.
In the third paper: The matrix does not have any conjugation, but rather the matrix consists of only t and k, which was also the question of mine.

Why it is
$$ \begin{pmatrix} E_{t1}\\ E_{t2} \end{pmatrix} =
\begin{pmatrix} t & k\\ -k^* & t^* \end{pmatrix}
\begin{pmatrix} E_{i1}\\ E_{i2} \end{pmatrix} $$ and not

$$ \begin{pmatrix} E_{t1}\\ E_{t2} \end{pmatrix} =
\begin{pmatrix} t & k\\ k & t \end{pmatrix}
\begin{pmatrix} E_{i1}\\ E_{i2} \end{pmatrix} $$

Most articles do not explain, they just use the matrix that they found in a book and then do some calculations.
Ok, so a little more digging is required. How about this:

https://hal.science/hal-00474731/document
 
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