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noppawit
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Two isotropic (radiating the same intensity of EM wave in all directions) point sources S1and S2 emit light in phase at wavelength λ and at the same amplitude. The sources are separated by distance 2d=6.00λ. They lie on the axis that parallel to the x-axis, which runs along a viewing screen at distance D=2.00λ. The origin lies on the perpendicular bisector between the sources. The figure below shows two rays reaching point P on the screen, at position xp
At what value of xp do the rays have the minimum possible phase difference?
http://www.wisheyebio.com/images/screen.png
From question, the minimum possible phase difference, does it mean that the first dark point, or not?
I tried like this...
[tex]\Delta L=d\sin \theta) = (m+0.5)\lambda[/tex]
[tex]\frac{2dx_{p}}{D} = 0.5\lambda[/tex]
[tex]\frac{6 \lambda x_{p}}{20\lambda}[/tex]
[tex]x_{p} = 1.66\lambda[/tex]
Am I correct or not?
At what value of xp do the rays have the minimum possible phase difference?
http://www.wisheyebio.com/images/screen.png
From question, the minimum possible phase difference, does it mean that the first dark point, or not?
I tried like this...
[tex]\Delta L=d\sin \theta) = (m+0.5)\lambda[/tex]
[tex]\frac{2dx_{p}}{D} = 0.5\lambda[/tex]
[tex]\frac{6 \lambda x_{p}}{20\lambda}[/tex]
[tex]x_{p} = 1.66\lambda[/tex]
Am I correct or not?
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