- #1
BMcC
- 32
- 0
On an inclined plane (φ = 12°), calculate the minimum force P required to pull the roller over the step. The radius of the roller, r = 0.685m
My attempt
The sum of the Moment force about the system = 0
0 = mg(sin(φ)*(r-h) + mg(cos(φ)*√[r2-(r-h)2] - P(cos(θ)*r-h)
P(cos(θ)*r-h) = mg(sin(φ)*(r-h) + mg(cos(φ)*√[r2-(r-h)2]
P(cos(32.9)*0.575m) = (26kg)(9.8)(sin(12)*(0.575) + (26)(9.8)(cos(12)*√[0.6852 - (0.575)2]
0.483*P = 30.46 + 92.79
P = 255.17
This answer appears to be wrong. Any help on this? I can't seem to figure out where I went wrong.