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wonguyen1995
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Find the minimum value of F(x)=\int_{x^2-2x}^{0} 1/(1+t^2)\,d
Does it has a maximum value? why?
Does it has a maximum value? why?
wonguyen1995 said:Find the minimum value of F(x)=\int_{x^2-2x}^{0} 1/(1+t^2)\,d
Does it has a maximum value? why?
The minimum value of a function is the smallest output value that the function can produce. It is the point on the graph of the function where the y-value is lowest.
The minimum value of a function can be determined by finding the critical points of the function, which are points where the slope of the curve is zero. These points can be found by taking the derivative of the function and setting it equal to zero. The smallest output value among these critical points is the minimum value of the function.
Yes, a function can have more than one minimum value. This can occur if the function has multiple local minimum points, which are points on the graph where the function is at a low point but not the absolute lowest point. However, a function can only have one absolute minimum value.
No, the minimum value and maximum value of a function are not always the same. The maximum value of a function is the highest output value that the function can produce, and it is the point on the graph where the y-value is highest. These values can be the same in some cases, but it is not always the case.
Yes, a function can have a minimum value even if it does not have a maximum value. This can occur if the function continues to decrease indefinitely, never reaching a maximum point. In this case, the minimum value would be the lowest possible output value for the function.