- #1
icesalmon
- 270
- 13
- Homework Statement
- Determine the minterms of F
- Relevant Equations
- Definition of minterm: A standard product term, also called a minterm, is a product term that includes each variable of the problem, either uncomplemented or
complemented.
I simplified the given function into a single minterm and a single maxterm
F(A,B,C,D) = ABC + (A + B + C) + AB
F(A,B,C,D) = AB(C+1) + (A+B+C)
F(A,B,C,D) = AB(1) + (A+B+C)
F(A,B,C,D) = AB + (A+B+C)
The only terms that involve a logical AND operation are AB as (A+B+C) is a maxterm of the function.
I am not sure if simplifying the function is necessary here and if I'm not supposed to for whatever reason I would think that either (AB) or (ABC) from the original function F(A,B,C,D) would be correct. Maybe ABC would be the best option because it includes all variables of the function. Regardless, none of the available solutions match what I believe the solution is and upon looking at the posted solution in the book it says AB'C is the solution. I'm totally lost as to where this minterm actually came from as it doesn' even appear in the original function. Is there some sort of algebraic manipulation going on here? What am I not seeing?
F(A,B,C,D) = ABC + (A + B + C) + AB
F(A,B,C,D) = AB(C+1) + (A+B+C)
F(A,B,C,D) = AB(1) + (A+B+C)
F(A,B,C,D) = AB + (A+B+C)
The only terms that involve a logical AND operation are AB as (A+B+C) is a maxterm of the function.
I am not sure if simplifying the function is necessary here and if I'm not supposed to for whatever reason I would think that either (AB) or (ABC) from the original function F(A,B,C,D) would be correct. Maybe ABC would be the best option because it includes all variables of the function. Regardless, none of the available solutions match what I believe the solution is and upon looking at the posted solution in the book it says AB'C is the solution. I'm totally lost as to where this minterm actually came from as it doesn' even appear in the original function. Is there some sort of algebraic manipulation going on here? What am I not seeing?