MHB Minutes, Degrees, Seconds to Radians

AI Thread Summary
To convert the angle of 12 degrees, 28 minutes, and 4 seconds into radians, first convert the entire angle to decimal degrees. This involves calculating 12 + (28/60) + (4/3600), resulting in approximately 12.4678 degrees. Then, multiply this value by π/180 to convert degrees to radians. The final expression for the angle in radians is approximately 11221π/162000. The discussion emphasizes the importance of understanding the conversions between degrees, minutes, seconds, and radians.
mathdad
Messages
1,280
Reaction score
0
Express the following angle in radians.

12 degrees, 28 minutes, 4 seconds that is, 12° 28' 4".

I cannot apply pi/180° to this problem.
 
Mathematics news on Phys.org
Use the same method I posted in your other thread, and use the fact that there are 3600 seconds in a degree. :D
 
Why can't you "apply pi/180" here?

You know that there are 60 seconds in a degree don't you? So 4''= 4/60= 0.06667 minutes approximately and 28' 4'' is 28.06667 minutes. And you know, I hope, that there are 60 minutes in a degree so that 28.06667 minutes is 28.06667/60= 0.4678 degrees. 12 degrees, 28 minutes, 4 seconds is 12.4678 degrees. Multiply that by pi/180.
 
MarkFL said:
Use the same method I posted in your other thread, and use the fact that there are 3600 seconds in a degree. :D

Is there another way to solve this problem?
 
RTCNTC said:
Is there another way to solve this problem?

What you want to do is convert strictly to degrees, and then to radians.

$$12^{\circ}28'4''=\left(12+\frac{28}{60}+\frac{4}{3600}\right)^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{11221\pi}{162000}$$
 
It's all coming back to me now.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Is it possible to arrange six pencils such that each one touches the other five? If so, how? This is an adaption of a Martin Gardner puzzle only I changed it from cigarettes to pencils and left out the clues because PF folks don’t need clues. From the book “My Best Mathematical and Logic Puzzles”. Dover, 1994.

Similar threads

Back
Top