- #1
Null_Void
- 73
- 8
- Homework Statement
- See pic
- Relevant Equations
- None
So I was able to find out quite easily the image distance after the first refraction and the corresponding magnification.
Employing Cartesian convention
Substituting the values gives us:
Thus the height of the image below the principal axis must be
I was also able to find the horizontal position of the final image.
Now the problem arises when calculating the final image height for the refraction by the second half-lens.
The distance between the plane mirror and the principal axis is while the image is formed below the principal axis (height). I can see that of the image is formed as a virtual object and here's where I'm stuck.
1) Can the real image formed by the first lens on the plane mirror give rise to a virtual image of the same size?
This is my first time encountering a scenario like this and I'm a bit skeptical
2) how do I establish a relationship between the virtual object and the corresponding final image formed? I'm confused as there's a lot of stuff going on.
3) Will the virtual image formed by the plane mirror of the first real image, act as an object for the second lens? I feel that it shouldn't as it isn't a virtual object but the book solution seems to assume it does.
The height of the final image is given as 8/3mm
Employing Cartesian convention
Substituting the values gives us:
Thus the height of the image below the principal axis must be
I was also able to find the horizontal position of the final image.
Now the problem arises when calculating the final image height for the refraction by the second half-lens.
The distance between the plane mirror and the principal axis is
1) Can the real image formed by the first lens on the plane mirror give rise to a virtual image of the same size?
This is my first time encountering a scenario like this and I'm a bit skeptical
2) how do I establish a relationship between the virtual object and the corresponding final image formed? I'm confused as there's a lot of stuff going on.
3) Will the virtual image formed by the plane mirror of the first real image, act as an object for the second lens? I feel that it shouldn't as it isn't a virtual object but the book solution seems to assume it does.
The height of the final image is given as 8/3mm