- #1
bcahmel
- 25
- 0
Homework Statement
Find the min and max of sin^3(x) - cos^2(x) on the interval [0,2pi]
The Attempt at a Solution
So I took the derivative, which is 3sin^2(x)cos(x) + 2cos(x)sin(x)
Then I set it to 0 and factored to get the crit pts:
0=(cosxsinx)(3sinx+2)
so cosx=0, sinx=0, and 3sinx+2=0
so x=pi, 2pi, 0, and -0.6184
And plugging these values into get the y's I got: -1,-1,-1,-0.8587
So is the max -1 and mix -0.8587? I think I messed up somewhere. Any help?