- #1
Jahnavi
- 848
- 102
Homework Statement
300gm of water at 25°C is added to 100gm of ice at 0°C ,find the final temperature of the mixture .Also find the final composition of mixture .
Homework Equations
[/B]
Specific heat of water = 1 cal/gm/°C
Latent heat of fusion of ice = 80 cal/gm
The Attempt at a Solution
[/B]
Heat released by 300gm water to reach 0°C = 300x1x25 = 7500 cal
Heat required by ice to melt completely
= 100x80= 8000 cal
Since heat supplied is less than heat required , whole ice will not melt .
Amount of ice melted = 7500/80 = 93.75gm
Final composition of mixture = 393.75gm water +6.25gm ice at 0°C
Is my answer correct ?
Last edited: