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sallychan
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Homework Statement
100 g of steam at 100 °C is mixed with 500 g of water at 25 °C. What is the final temperature of the mixture?
Homework Equations
Q= mL
Q= mcΔT
The Attempt at a Solution
Heat given by to water = heat loss at condensation
= mLv
= (0.1) (2.26 E 6)
= 226000 J
Maximum possible heat water can take = mc ΔT
= (0.5) (4186)(100-25)
= 156975 J
Because water does not take up all the latent heat from steam, only some of the steam condensate.
I wonder is my conclusion right? Or will latent heat given by steam actually boils water?
Thanks!
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