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OP warned about not using the homework template
Say we have a mixture of 10 mL of methane and propane. For a complete combustion, we need 41 mL of O2. Calculate the composition of the mixture in terms of volume, if atmospheric temperature and pressure are constants.
The equations are:
CH4 + O2 --> CO2 + H2O
C3H8 + O2 --> CO2 + H2O
I do not understand the question: am I asked to calculate a percentage of volumes, e.g. VCH4/VC3H8, or simply to find the volumes of CH4 and C3H8 separately (if so, how?)? Am I considering the reactives or the products of the reaction?
These calculations must come in somewhere in the solution:
I know that all gazes have the same molecular volume at normal temperature and pressure: 22.4L/mol. Therefore I can determine the quantity of moles of each component. In the initial mixture (before reaction), there is:
0.224mol of CH4 + C3H8
0.918mol of O2.
Thx. for helping!
The equations are:
CH4 + O2 --> CO2 + H2O
C3H8 + O2 --> CO2 + H2O
I do not understand the question: am I asked to calculate a percentage of volumes, e.g. VCH4/VC3H8, or simply to find the volumes of CH4 and C3H8 separately (if so, how?)? Am I considering the reactives or the products of the reaction?
These calculations must come in somewhere in the solution:
I know that all gazes have the same molecular volume at normal temperature and pressure: 22.4L/mol. Therefore I can determine the quantity of moles of each component. In the initial mixture (before reaction), there is:
0.224mol of CH4 + C3H8
0.918mol of O2.
Thx. for helping!
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