Modeling a (rotating) mass impact on a preloaded (rotational) spring

In summary, the mass will rotate until it hits a stop due to the applied external forces. If the external forces are increasing, the mass will hit a certain point where there is a preloaded spring that will then deflect.
  • #1
vipers120
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TL;DR Summary
Numerical modeling of a system in which there is a mass rotating freely up to a certain point at which there is a preloaded spring.
I am trying to model numerically the following system:
A rigid body mass is rotating freely around an axis (no rotational stiffness/damping) within a range, let's assume plus-minus 3 degrees for now.
Case A. The external forces on the mass are low and keep changing which results in the situation the angle of the rotating mass is within the range.
Case B. When the external forces on the mass are increasing, we hit a kind of end-stop at 3 degrees. From this point onwards, there is a (rotational) spring which is preloaded relatively high, let's say we have 10 000Nm of pre-load. After this pre-load, the spring stiffness is very low which means there will be not so much more than 10 000Nm given back to the mass.

I'm having issues modeling Case B, especially the time of hitting, i.e. the impact.

My thinking is:
If the incoming velocity (and thus Kinetic Energy) is high enough, the energy is higher that is stored in the pre-loaded spring and thereby will start to deform.
If the incoming velocity (and thus Kinetic Energy) is low, the energy is lower then stored in the pre-loaded spring and thereby will not deform.

1. Is this thinking correct in the first place? I was also thinking trying to approach this problem in terms of moments, because the pre-load is in terms of moments. However, then I don't know how to obtain the moment related to the impact.
2. How to calculate the energy stored in a pre-loaded spring?
3. If the incoming velocity is low, how to approach the impact: how do I model the impact correctly?

I've been trying to look into this topic online and on this forum but did not find similar problems.
 
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  • #2
Start with the simplest approach. Assume an impact with a perfectly rigid surface, and a constant torque of 10,000 Nm after any deflection. The calculation is simply the rotation angle to decelerate to zero velocity at constant torque. If the impact energy is small, the deflection will be small, but there will be deflection. There must be deflection because otherwise a finite mass with finite energy impacting a rigid surface would have infinite torque.

The more complex approach is to assume a contact stiffness. Any real object in contact with another real object will have a deflection that is some function of the contact force. Search contact mechanics to find some good information on this. In that case, you would calculate the contact stiffness and use that contact stiffness to calculate a peak deflection, use that peak deflection to calculate the peak torque. If the peak torque exceeded 10,000 Nm, the spring would deflect. The spring torque would be a constant 10,000 Nm during spring deflection.

The even more complex approach is to take the above approach, and add in the spring stiffness. If the total spring deflection is small, this adds complexity without adding accuracy.

There are interesting numerical challenges when modelling contact. Those challenges can easily suck you down into a black hole. Try very hard to make the simplest approach work.
 
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  • #3
jrmichler said:
Start with the simplest approach. Assume an impact with a perfectly rigid surface, and a constant torque of 10,000 Nm after any deflection. The calculation is simply the rotation angle to decelerate to zero velocity at constant torque. If the impact energy is small, the deflection will be small, but there will be deflection. There must be deflection because otherwise a finite mass with finite energy impacting a rigid surface would have infinite torque.

The more complex approach is to assume a contact stiffness. Any real object in contact with another real object will have a deflection that is some function of the contact force. Search contact mechanics to find some good information on this. In that case, you would calculate the contact stiffness and use that contact stiffness to calculate a peak deflection, use that peak deflection to calculate the peak torque. If the peak torque exceeded 10,000 Nm, the spring would deflect. The spring torque would be a constant 10,000 Nm during spring deflection.

The even more complex approach is to take the above approach, and add in the spring stiffness. If the total spring deflection is small, this adds complexity without adding accuracy.

There are interesting numerical challenges when modelling contact. Those challenges can easily suck you down into a black hole. Try very hard to make the simplest approach work.
Many thanks for your reply. I think I understand what you mean with your approaches.

I still have a little bit doubts in comparing the simplest approach with the more complex approach.

Using the simplest approach, you assume the restraint torque given to the mass would be 10 000Nm, constantly. This, depending on the velocity and inertia of the system, of course for a small time.
Using the more complex approach, you assume the restraint torque given to the mass could be somewhere ranging between 0 - 10 000Nm, using a finite stiffness in the case the deflection (in combination with the stiffness) would lead to a lower than 10 000 Nm.

These are, in my opinion, two quite different approaches with quite different solutions, aren't they?
 
  • #4
Try the simplest approach. If the results are satisfactory, stop. If not, go to a more sophisticated approach. Repeat until the results are satisfactory.

Trying to figure out what is the best approach before actually trying the simplest approach is an example of "paralysis by analysis". A lot of numerical analysis is like that. Get something to work, then decide if you really need to make it better.
 
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FAQ: Modeling a (rotating) mass impact on a preloaded (rotational) spring

What is the purpose of modeling a mass impact on a preloaded spring?

The purpose of this type of modeling is to understand and predict the behavior of a system where a mass is impacting a preloaded spring. This can be useful in various engineering and physics applications, such as designing shock absorbers or analyzing the motion of a pendulum.

How does the mass of the object affect the spring's behavior?

The mass of the object has a direct impact on the spring's behavior. A heavier mass will cause the spring to compress more, while a lighter mass will cause less compression. This is due to the relationship between force, mass, and acceleration described by Newton's Second Law.

What factors determine the amount of energy stored in the spring during impact?

The amount of energy stored in the spring during impact is determined by several factors, including the mass of the object, the velocity of the impact, and the stiffness of the spring. A higher mass or velocity will result in more energy being stored in the spring, while a stiffer spring will require more energy to be compressed.

How does the spring's preload affect the impact of the mass?

The preload of the spring, or the initial compression applied to the spring, can significantly affect the impact of the mass. A higher preload will result in a stiffer spring, which will cause the mass to experience a larger force and a shorter displacement upon impact. This can be seen in the equation for spring force, where the preload is represented as the initial displacement of the spring.

What are some real-world applications of modeling a mass impact on a preloaded spring?

This type of modeling has many real-world applications, such as designing car suspension systems, analyzing the motion of a bouncing ball, and studying the behavior of a pogo stick. It can also be used in sports equipment, such as designing the perfect tennis racket or golf club, to optimize the impact of the ball on the spring-like components of the equipment.

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