- #1
Craig91
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Hello new to the forum.
I'm a builder by trade and enjoy studying the concepts behind the things I build.
My problem is:
A typical concrete post and base panel with a wooden fence. Unit mass approximately 350kgs including the foundation concrete around the posts.
2.0m wide x 2.0m above ground. 0.5m depth below ground. Figures adjusted for ease.
0.1 x 0.1m concrete posts.
If I take a figure of 0.5kN/m^2 for lateral storm wind load, that gives a lateral load of 2Kn.
How do I model the reaction force from the foundations, such that the unit won't tip over?
If I imagine the problem as a seesaw type arrangement, then where do I put the fulcrum:
If I look at it as a seesaw arrangement about ground level, then I get a reaction force of 8kN.
If I look at it from a moment arrangement using a footing width of 0.3m, then I get a reaction force needed of 6.66kN.
Either way the reaction force needed is much bigger than the weight of the unit approx 3.5kN . Therefore how much do the following factors come into play:
Also how does the lower centre of gravity due to the concrete base panels affect the system?
Thanks in advance,
Craig
I'm a builder by trade and enjoy studying the concepts behind the things I build.
My problem is:
A typical concrete post and base panel with a wooden fence. Unit mass approximately 350kgs including the foundation concrete around the posts.
2.0m wide x 2.0m above ground. 0.5m depth below ground. Figures adjusted for ease.
0.1 x 0.1m concrete posts.
If I take a figure of 0.5kN/m^2 for lateral storm wind load, that gives a lateral load of 2Kn.
How do I model the reaction force from the foundations, such that the unit won't tip over?
If I imagine the problem as a seesaw type arrangement, then where do I put the fulcrum:
- ground level
- opposite diagonal to the pushing force. i.e. opposite bottom corner to push force
- or two thirds depth of embedment as point of rotation (I came across this figure in a couple of old texts)
If I look at it as a seesaw arrangement about ground level, then I get a reaction force of 8kN.
If I look at it from a moment arrangement using a footing width of 0.3m, then I get a reaction force needed of 6.66kN.
Either way the reaction force needed is much bigger than the weight of the unit approx 3.5kN . Therefore how much do the following factors come into play:
- Load sharing between adjacent panels
- Reaction forces from the soil
Also how does the lower centre of gravity due to the concrete base panels affect the system?
Thanks in advance,
Craig