- #1
fish
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Is this how you work this problem:
A sulfuric acid solution has a density of 1.49 g/mL and contains 59 percent H2SO4
by mass. what is the molarity of this solution?
.59x98g = 57.82g H2SO4
1mL/1.49g x 57.82g H2SO4 = .0388L
57.82g H2SO4/ 98g H2SO4 = .59 mol
.59 mol/.0388L = 15.206 M H2SO4
A sulfuric acid solution has a density of 1.49 g/mL and contains 59 percent H2SO4
by mass. what is the molarity of this solution?
.59x98g = 57.82g H2SO4
1mL/1.49g x 57.82g H2SO4 = .0388L
57.82g H2SO4/ 98g H2SO4 = .59 mol
.59 mol/.0388L = 15.206 M H2SO4