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This is my first time posting in this site so if I left out any information or the information needs to be formatted differently I apologize ahead of time.
Determine the moment of inertia of the area about the y axis.
The curve is represented by y2=2x, and the shaded region is the smaller area above the curve.
0m<x<2m
0m<y<2m
Is the parallel axis theorem needed? If it is, why is the reason?
Since the problem asks for moment of Intertia about the y-axis
1. Iy= ∫x2dA.
2. I chose my dA to be xdy because I need to find a "bar" perpendicular to the axis I am trying to find the moment of inertia about.
3. Solved
Iy= ∫x2ydx.
I substituded (2-/sqrt(2x)) for y and solved for the integral from (0<x<2)
My answer I got was 2.13m4 and the answer is incorrect.
Is my process correct or do I need to find different limits of integration?
Homework Statement
Determine the moment of inertia of the area about the y axis.
The curve is represented by y2=2x, and the shaded region is the smaller area above the curve.
0m<x<2m
0m<y<2m
Homework Equations
Is the parallel axis theorem needed? If it is, why is the reason?
The Attempt at a Solution
Since the problem asks for moment of Intertia about the y-axis
1. Iy= ∫x2dA.
2. I chose my dA to be xdy because I need to find a "bar" perpendicular to the axis I am trying to find the moment of inertia about.
3. Solved
Iy= ∫x2ydx.
I substituded (2-/sqrt(2x)) for y and solved for the integral from (0<x<2)
My answer I got was 2.13m4 and the answer is incorrect.
Is my process correct or do I need to find different limits of integration?